如何解析用逗号分隔的列?

时间:2018-01-26 20:46:34

标签: sql sql-server string parsing

我有以下选择查询(使用SQL Server 2017):

SELECT PAYMENT_INFO
FROM CHECK_PAYMENT
WHERE (PAYMENT_FISCAL_DATE = '01/19/2018')
  AND (TENDER_MEDIA_NAME LIKE 'PaymentCard%')
ORDER BY VOID, TENDER_MEDIA_NAME

输出是一个非常长的分号分隔字符串,我想只返回前两个字段。

当前输出:

AmericanExpress;XXXXXXXXXXX4111;;;;41.47;8.00...............
MasterCard;XXXXXXXXXXXX7971;;;;40.22;10.00................
Visa;XXXXXXXXXXXX6302;;;;11.94;0.00....................

期望的输出:

AmericanExpress;XXXXXXXXXXX4111
MasterCard;XXXXXXXXXXXX7111
Visa;XXXXXXXXXXXX6111

如果可能的话,我希望将它们分成两列。

我查看过堆栈并发现了类似的问题,但没有找到有效的答案,或者我可以弄清楚如何修改我的情况。

3 个答案:

答案 0 :(得分:1)

创建以下功能。

CREATE FUNCTION dbo.ColumnSplitter
(
  @String VARCHAR(MAX),
  @NroSubString INT,
  @Separator VARCHAR(5)
)
RETURNS VARCHAR(MAX) AS
BEGIN
    DECLARE @St INT = 0, @End INT = 0, @Ret VARCHAR(MAX)
    SET @String = @String + @Separator
    WHILE CHARINDEX(@Separator, @String, @End + 1) > 0 AND @NroSubString > 0
    BEGIN
        SET @St = @End + 1
        SET @End = CHARINDEX(@Separator, @String, @End + 1)
        SET @NroSubString = @NroSubString - 1
    END
    IF @NroSubString > 0
        SET @Ret = ''
    ELSE
        SET @Ret = SUBSTRING(@String, @St, @End - @St)
    RETURN @Ret
END
GO

然后在查询中使用它。

SELECT dbo.ColumnSplitter(PAYMENT_INFO, 1, ';') as FirstColumn,
       dbo.ColumnSplitter(PAYMENT_INFO, 2, ';') as SecondColumn      
FROM CHECK_PAYMENT
WHERE (PAYMENT_FISCAL_DATE = '01/19/2018')
  AND (TENDER_MEDIA_NAME LIKE 'PaymentCard%')

答案 1 :(得分:0)

这将返回单个列,其值以分号分隔:

declare @example as table (
    exampleid int identity(1,1) not null primary key clustered
,   value_ nvarchar(255) not null
);

insert into @example (value_)

select 'AmericanExpress;XXXXXXXXXXX4111;;;;41.47;8.00...............' union all
select 'MasterCard;XXXXXXXXXXXX7971;;;;40.22;10.00................' union all
select 'Visa;XXXXXXXXXXXX6302;;;;11.94;0.00....................'

select substring(value_, 0, charindex(';', value_, charindex(';', value_) + 1)) Payment_Info
  from @example

答案 2 :(得分:0)

SELECT        LEFT(PAYMENT_INFO, 
                   CHARINDEX(';', PAYMENT_INFO, 
                             CHARINDEX(';', PAYMENT_INFO) + 1))
FROM          CHECK_PAYMENT
WHERE        (PAYMENT_FISCAL_DATE = '01/19/2018')
     AND (TENDER_MEDIA_NAME LIKE 'PaymentCard%')
ORDER BY VOID, TENDER_MEDIA_NAME