Question

有更好或更有效的方法吗？

这两个对象都有相同的Id和一些我想要更新的类似字段。

foreach (var i in oldItems)
{
   foreach (var j in newItemValues)
   {
       if(i.id == j.Id)
       {
           j.field1 = (decimal)i.field1;
           j.field2 = (decimal)i.field2;
       }
   }
}

Answer 1

试试这个也许你就是这样;

<div class="jumbotron jumbotron-fluid">
  <div class="container">
    <img src="https://cdn.officialpsds.com/imageview/78/5z/785z6w_large.png?1395542934" alt="">
  </div>
</div>

Answer 2

在循环之前将oldItems或newItemValues转换为地图。

这会将计算复杂度从O（n ^ 2）降低到O（n）

Answer 3

您可以newItemsValues = (from t1 in oldItems join t2 in newItemsValues on t1.Id equals t2.Id select new YourModel { field1 = t1.field1 ,field2 = t1.field2 } ).ToList();

执行此操作

oldItems Id

结果会列出newItemsValues Id等于public void rightClick() { TimerTask task; task = new TimerTask() { @Override public void run() { System.out.println("X: " + mouseConverter(mouseX) + " Y: " + mouseConverter(mouseY)); System.out.println("SX: " + select.x + " SY: " + select.y); if (select.x != mouseConverter(mouseX) || select.y != mouseConverter(mouseY)) { int[][] path = select.ai().getPath(arena, mouseConverter(mouseX), mouseConverter(mouseY), blocked); select.move(path[0][0], path[0][1]); repaint(); } else { cancel(); } } }; timer.schedule(task, 0, ANIMATION_DELAY); }的所有匹配项目

Answer 4

capabilites

如果您想从newItemValues = (from a in oldItems join b in newItemValues on a.id equals b.id select new YourClass() {field1 = b.field1 ... }).ToList();

获取所有值，也可以使用select b

当然，您必须添加b

从另一个列表更新一个列表中的字段

4 个答案: