Question

您好，我现在正在使用php我的管理员学习SQL。我在使用INSERT INTO时遇到了一些麻烦。我查看了如何创建INSERT INTO的语法，但我总是得到一个错误，我的版本错误。有谁知道我做错了什么？

   CREATE TABLE patient1(
patient_id INT (3) NOT NULL AUTO_INCREMENT,
place VARCHAR (20) NOT NULL,
profession VARCHAR (30)NOT NULL,
age INT (11),
PRIMARY KEY (patient_id)
)

INSERT INTO patient (patient_id, place, profession, age) VALUES (101, 'Indiana','Software', 23);
INSERT INTO patient (patient_id, place, profession, age) VALUES(102, 'Ohio', 'Teacher',45);
INSERT INTO patient (patient_id, place, profession, age) VALUES(103, 'Ohio', 'Doctor', 65);
INSERT INTO patient (patient_id, place, profession, age) VALUES(104, 'Indiana', 'Software', 34);
INSERT INTO patient (patient_id, place, profession, age) VALUES(105, 'Wisconsin', 'Pharmacist', 69);

Answer 1

因为patient_id具有自动递增，所以您不需要在声明中包含它。

INSERT INTO patient (place, profession, age) 
VALUES ('Indiana','Software', 23);

修改

仔细检查代码后，问题是您为表patient1命名，但是插入patient

检查 demo 以查看是否有效

Answer 2

请正确检查您的表名。这就是问题所在。

INSERT INTO patient1 (patient_id, place, profession, age) VALUES (101, 'Indiana','Software', 23);
INSERT INTO patient1 (patient_id, place, profession, age) VALUES(102, 'Ohio', 'Teacher',45);
INSERT INTO patient1 (patient_id, place, profession, age) VALUES(103, 'Ohio', 'Doctor', 65);
INSERT INTO patient1 (patient_id, place, profession, age) VALUES(104, 'Indiana', 'Software', 34);
INSERT INTO patient1 (patient_id, place, profession, age) VALUES(105, 'Wisconsin', 'Pharmacist', 69);

将数据放入表中

2 个答案: