Question

我正在尝试为第三方C DLL编写Python包装器。

函数WolaInit初始化库并返回一个句柄，用于后续函数调用。

import ctypes

# Load WOLA DLL into memory.
wolaDLL = ctypes.WinDLL("wola.dll")

# Function prototypes
WolaInit = wolaDLL.WolaInit
WolaInit.restype = ctypes.c_ulong
WolaInit.argtypes = [
        ctypes.c_int,              # La
        ctypes.c_int,              # Ls
        ctypes.c_int,              # R
        ctypes.c_int,              # N
        ctypes.c_int]              # stacking

WolaGetStacking = wolaDLL.WolaGetStacking
WolaGetStacking.restype = ctypes.c_int
WolaGetStacking.argtypes = [ctypes.c_ulong]

# Parameters
La = 128
Ls = 64
R = 32
N = 8
stacking = 0

# Initialize
wolaHandle = WolaInit(La, Ls, R, N, stacking)
print('Handle: ' + hex(wolaHandle))

# Test if library was initialized
stackingVal = WolaGetStacking(wolaHandle)

但是，在使用返回的句柄时，会发生访问冲突（访问冲突的地址对应于句柄值加上一个额外的偏移量）。

Handle: 0x3fe22310

Traceback (most recent call last):

  File "<ipython-input-47-5ba1f23d5c33>", line 1, in <module>
    runfile('D:/Projects/Desyncra_611110600/Simulations/WOLA/wola.py', wdir='D:/Projects/Desyncra_611110600/Simulations/WOLA')

  File "C:\ProgramData\Anaconda3\lib\site-packages\spyder\utils\site\sitecustomize.py", line 710, in runfile
    execfile(filename, namespace)

  File "C:\ProgramData\Anaconda3\lib\site-packages\spyder\utils\site\sitecustomize.py", line 101, in execfile
    exec(compile(f.read(), filename, 'exec'), namespace)

  File "D:/Projects/Desyncra_611110600/Simulations/WOLA/wola.py", line 69, in <module>
    stackingVal = WolaGetStacking(wolaHandle)

OSError: exception: access violation reading 0x000000003FE22328

这种访问冲突的原因是什么？如何解决？

Answer 1

句柄通常实现为指针。在64位系统上，指针是64位。在Windows上，c_ulong是32位。我认为你正在截断句柄，但没有看到函数原型，它只是一个理论。 c_void_p可能是句柄更合适的类型。

Python ctypes：访问冲突

1 个答案: