Question

我有一个Oracle SQL DB列，其中包含逗号分隔的值列表，作为输入，我有两个数字 - 我需要查明值列表中至少有一个数字是否在两个输入数字之间。

示例：
数据库列内容：'100, 200, 300, 400, 500'
输入：10,100
请求的输出：true（因为100在10到110之间）。

输入：10,80。
请求的输出：false。

有没有办法在直接SQL（无PL / SQL）中做到这一点？

Answer 1

您可以使用XMLTABLE。

Oracle 11g R2架构设置：

create table yourtable as select '100, 200, 300, 400, 500' nums from dual;

查询1 ：

 WITH t(n)
     AS (SELECT TO_NUMBER (column_value)
         FROM   yourtable,
                XMLTABLE(nums)),
     input(min_val, max_val)
     AS (SELECT Min(TO_NUMBER(column_value)),
                Max(TO_NUMBER(column_value))
         FROM   XMLTABLE('10,100' ))
SELECT CASE
         WHEN EXISTS (SELECT 1
                      FROM   t
                      WHERE  t.n BETWEEN i.min_val AND i.max_val) THEN 'TRUE'
         ELSE 'FALSE'
       END is_between
FROM   input i

<强> Results ：

| IS_BETWEEN |
|------------|
|     TRUE   |

Answer 2

您可以创建如下函数：

CREATE OR REPLACE TYPE NUMBER_TABLE_TYPE AS TABLE OF NUMBER;

CREATE OR REPLACE FUNCTION SplitCSV(LIST IN VARCHAR2, Separator IN VARCHAR2) RETURN NUMBER_TABLE_TYPE IS
    OutTable NUMBER_TABLE_TYPE := NUMBER_TABLE_TYPE();  
BEGIN
    SELECT REGEXP_SUBSTR(LIST, '[^'||Separator||']+', 1, LEVEL) 
    BULK COLLECT INTO OutTable
    FROM dual
    CONNECT BY REGEXP_SUBSTR(LIST, '[^'||Separator||']+', 1, LEVEL) IS NOT NULL;

    RETURN OutTable;
END;

然后你可以使用它，例如：

WITH t AS (SELECT '100, 200, 300, 400, 500' AS val FROM dual)
SELECT distinct 'true'
FROM t
    CROSS JOIN TABLE(SplitCSV(val, ','))
WHERE COLUMN_VALUE BETWEEN 10 and 80;

或者在一个SELECT中完成所有操作：

WITH t AS 
    (SELECT TO_NUMBER(REGEXP_SUBSTR('100, 200, 300, 400, 500', '[^,]+', 1, LEVEL)) AS NUMBERS
    FROM dual
    CONNECT BY REGEXP_SUBSTR('100, 200, 300, 400, 500', '[^,]+', 1, LEVEL) IS NOT NULL)
SELECT case when count(NUMBERS) > 0 then 'TRUE' else 'FALSE' end 
FROM t
WHERE NUMBERS BETWEEN 10 AND 80;

SQL解析值列表，查找大于/小于/范围

2 个答案: