Question

如何将if语句写入python代码，接下来列出哪些规则。代码必须检查是否任何5x5矩阵是宾果游戏。这是我的代码：

                      #Rules are simple
 table=[[12,17,34,48,70],  #first column integers are allowed 1-15         
  [14,25,40,56,61],   #second column integers are allowed 16-30
  [6,30,43,46,72],    #third column integers are allowed 31-45
  [12,16,42,63,65],   #fourth column integers are allowed 46-60
  [4,31,34,49,67]]    #fifth column integers are allowed 61-75

def is_right_matrix(table):
    for i in range(len(table)):
        for j in range(len(table[i])):
            if 
                return False
        return True

Answer 1

（我希望我能正确理解你的问题。）

您可以查看所有数字并检查是否存在范围内（特定于每列）。如果没有，则返回False。

这个（不那么漂亮）示例适用于NumPy数组以及“嵌套”列表（如表示例中的那个）

table=[[12,17,34,48,70],       
  [14,25,40,56,61],
  [6,30,43,46,72],
  [12,16,42,63,65],
  [4,31,34,49,67]] 


def is_valid_matrix(table):
    for i, col in enumerate(table):  
        # i is the index of the column 
        # (so we know to which column each number belongs)
        # col is the current column

        # if the current column is the first column (indexes start at 0),
        # check for numbers from 1 to 15:
        if i == 0:  
            for n in col:  # go through every number in that column
                # check if that number is not in the range 1 to 15 
                # (range includes the first argument, but excludes the second)
                if n not in range(1, 16):
                # if so, immediately return False 
                # (and therefore exit out of the function)
                    return False  

        # if the current column is the second column,
        # check for numbers from 16 to 30:
        elif i == 1:
            for n in col:
                # check if that number is not in the range 16 to 31 
                if n not in range(16, 31):
                    return False

        # and so on

        elif i == 2:
            for n in col:
                if n not in range(31, 46):
                   return False

        elif i == 3:
            for n in col:
                if n not in range(46, 61):
                    return False

        elif i == 4:
            for n in col:
                if n not in range(61, 76):
                    return False

    return True  # if all "checks" passed/every number was valid: return True

Answer 2

这是一个过于复杂的解决方案，但它包含额外的唯一性测试（宾果表中不允许重复）。

def is_valid(matrix):

    floor = range(1, 62, 15)                  
    ceiling = range(15, 76, 15)               

    i = 0

    while i < len(floor):                       
        for low, high in zip(floor, ceiling):    
            for j in list(range(len(matrix)):
                if high < matrix[j][i] < low:
                    return False
        i += 1

    flat = sum(matrix, [])

    if len(set(flat) != len(flat):
        return False

    return True

根据宾果规则检查是否为5x5矩阵

2 个答案: