Question

我希望执行＆＃34;每周更新＆＃34;之前＆＃34;每日检查＆＃34;如下。这意味着＆＃34; time.Time＆＃34;应该把＆＃34; timeChan＆＃34;当主要功能开始运行时，等待超过两秒后立即而不是这样做。

结果应该是这样的

weekly updated
daily check
daily check
daily check
daily check
weekly updated
daily check
daily check
daily check
daily check
...

当然，我可以打印＆＃34;每周更新＆＃34;首先是一次，但有一种优雅的方法？

代码如下

package main

import "time"
import "fmt"

func main() {
    var a int
    timeChan := time.NewTicker(time.Second * 2).C

    tickChan := time.NewTicker(time.Millisecond * 500).C

    for {
        select {
        case <-timeChan:
            fmt.Println("weekly updated")
            a = 1
        case <-tickChan:
            if a == 1 {
                fmt.Println("daily check")
            } else {
                fmt.Println("Not update？")
            }
        }
    }
}

结果如下

Not update？
Not update？
Not update？
weekly updated
daily check
daily check
daily check
daily check
weekly updated
daily check
daily check
daily check
daily check
...

Answer 1

首先在weekly设置time.Millisecond的代码。然后在第一次完成时更改它。

package main

import (
    "fmt"
    "time"
)

func main() {
    var a = 0

    ticker := time.NewTicker(1)
    timeChan := ticker.C
    tickChan := time.NewTicker(time.Millisecond * 500).C

    for {
        select {
        case <-timeChan:
            fmt.Println("weekly updated")
            if a == 0 {
                ticker.Stop()
                timeChan = time.NewTicker(time.Second * 2).C
            }
            a = 1
        case <-tickChan:
            if a == 1 {
                fmt.Println("daily check")
            } else {
                fmt.Println("Not update？")
            }
        default:
        }
    }
}

输出：

weekly updated
daily check
daily check
daily check
daily check
weekly updated

Answer 2

将工作放在一个函数中并调用它。

var a int
timeChan := time.NewTicker(time.Second * 2).C
tickChan := time.NewTicker(time.Millisecond * 500).C
f := func() {
    fmt.Println("weekly updated")
    a = 1
}
f()
for {
    select {
    case <-timeChan:
        f()
    case <-tickChan:
        if a == 1 {
            fmt.Println("daily check")
        } else {
            fmt.Println("Not update？")
        }
    }
}

当函数开始在golang中运行时如何立即执行ticker

2 个答案: