Question

这些是我写的代码块：

$url = "http://links";
        $curl_post_data = array(
          "username" => "guest",
        );
$curl = curl_init($url);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_PORT, 8889);
curl_setopt($curl, CURLOPT_POST, true);
curl_setopt($curl, CURLOPT_POSTFIELDS, $curl_post_data);
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, true);
$curl_response = curl_exec($curl);
curl_close($curl);
$result = $curl_response;
echo $result

我尝试的是回显$ result变量并返回如下：

  {
        "price": [
            {
                "price": "2000",
                "origin_name": "JPN",
            },
            {
                "price": "5000",
                "origin_name": "USA",
            }
        ]
   }

我想要和需要知道的是如何获取或访问price和origin_name的每个元素的值。我尝试使用$result[0]['price']['origin_name'][0]进行调用，但它不起作用并返回如下：

Warning: Illegal string offset 'price' in .... on line ...

Warning: Illegal string offset 'origin_name' in .... on line ... 
{

我也尝试使用foreach函数编写，如下所示：

foreach($result['price'] as $res){
            echo $res[0];
}

但是它返回了相同的错误消息：

Warning: Illegal string offset 'price' in .... on line ...

Warning: Invalid argument supplied for foreach() in  .... on line ...

Answer 1

让我们假设从开始：

$result = '{
    "price": [
        {
            "price": "2000",
            "origin_name": "JPN"
        },
        {
            "price": "5000",
            "origin_name": "USA"
        }
    ]
}';
$resultDecoded = json_decode($result, true);
foreach ($resultDecoded["price"] as $item) {
    echo $item["price"];
}

问题是JSON String表示一个对象，而不是一个数组

注：

您向我们展示的JSON字符串格式不正确，不应在JSONString对象的最后一个属性的末尾添加逗号。

Answer 2

有时在使用之前需要修复的结果需要修复。可以使用preg_replace()来修复无效的JSON。将经过修复的JSON解码为PHP关联数组后，可以使用array_pop()提取价格数组，然后使用array_walk_recursive()获取价格和原始名称信息，如下所示：

<?php
// take badly formatted JSON ...
$result = '{
        "price": [
            {
                "price": "2000",
                "origin_name": "JPN",
            },
            {
                "price": "5000",
                "origin_name": "USA",
            }
        ]
   }';

// ... and remove the superfluous commas:
$pat = "/(o.+),/";
$replace = "$1";
$nu_result = preg_replace($pat,$replace,$result);

// now convert JSON into PHP array and traverse it
$resultDecoded = json_decode($nu_result, true);
$arr = array_pop($resultDecoded);
array_walk_recursive($arr,function($e,$i) {
       if ($i == "price") {
            echo "price: ",$e,"\n";
       }
       else
       if ($i == "origin_name") {
           echo "origin_name: ",$e,"\n\n";
       }
});

请参阅live code

PHP访问多维关联数组

2 个答案: