我使用FCM Cloud Messaging服务,我可以从服务器一次生成一些通知。但唯一的问题是,我能够打开第一个通知,但是从第2个通知开始,直到剩下的通知在我点击它们时都没有做任何事情。
消息服务代码:
public class MyFirebaseMessagingService extends FirebaseMessagingService {
private final String NOTIFICATION_TYPE = "type";
private final String NOTIFICATION_ID = "id";
private final String NOTIFICATION_TYPE_PRODUCT_DETAIL = "productdetail";
@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
super.onMessageReceived(remoteMessage);
String title = remoteMessage.getNotification().getTitle();
String body = remoteMessage.getNotification().getBody();
String token = remoteMessage.getFrom();
Log.d("FireBase TAG: ", token);
// Check if message contains a data payload.
if (remoteMessage.getData().size() > 0) {
Log.d("FireBaseMessageService","FireBase Data payload : " + remoteMessage.getData());
}
// Check if message contains a notification payload.
if (remoteMessage.getNotification() != null) {
Log.d(TAG, "Message Notification Body: " + remoteMessage.getNotification().getBody());
}
}
@Override
public void handleIntent(Intent intent) {
String type = intent.getExtras().getString(NOTIFICATION_TYPE, "");
int id = 0;
try {
id = Integer.valueOf(intent.getExtras().getString(NOTIFICATION_ID, ""));
} catch (NumberFormatException e) {
e.printStackTrace();
}
//Intents
Intent mainIntent = MainActivity.newIntent(this);
Intent editProfileIntent = EditProfileActivity.newIntent(this);
Intent settingsIntent = SettingsActivity.newIntent(this);
Intent productIntent = ProductActivity.newNotificationIntent(this, id, false, true);
if (UserManager.getSingleton().isUserLoggedIn(getApplicationContext())) {
PendingIntent pendingIntent;
if (type.equalsIgnoreCase(NOTIFICATION_TYPE_PRODUCT_DETAIL)) {
TaskStackBuilder stackBuilder = TaskStackBuilder.create(this);
stackBuilder.addParentStack(MainActivity.class);
stackBuilder.addNextIntent(mainIntent);
stackBuilder.addNextIntent(productIntent);
editProfileIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
pendingIntent = stackBuilder.getPendingIntent(0, PendingIntent.FLAG_ONE_SHOT);
} else if (type.isEmpty() || type.equals("")){
pendingIntent = PendingIntent.getActivity(this, 0, mainIntent,
PendingIntent.FLAG_ONE_SHOT);
} else {
TaskStackBuilder stackBuilder = TaskStackBuilder.create(this);
stackBuilder.addParentStack(MainActivity.class);
stackBuilder.addNextIntent(mainIntent);
stackBuilder.addNextIntent(productIntent);
pendingIntent = stackBuilder.getPendingIntent(0, PendingIntent.FLAG_ONE_SHOT);
}
Bitmap icon = BitmapFactory.decodeResource(getResources(),
R.drawable.onerm_logo_rounded);
NotificationCompat.Builder builder = new NotificationCompat.Builder(this)
.setSmallIcon(R.drawable.oneringgit_transparent)
.setLargeIcon(icon)
.setContentTitle(intent.getExtras().getString("gcm.notification.title"))
.setContentText(intent.getExtras().getString("gcm.notification.body"))
.setDefaults(NotificationCompat.DEFAULT_VIBRATE)
.setPriority(NotificationCompat.PRIORITY_MAX)
.setContentIntent(pendingIntent)
.setAutoCancel(true)
.setColor(getBaseContext().getResources().getColor(R.color.colorPrimary));
NotificationManager manager = (NotificationManager) getSystemService(NOTIFICATION_SERVICE);
manager.notify(id, builder.build());
}
}
我怀疑它与" id"有关。变量我放入manager.notify()方法。
有没有办法解决这个问题?
答案 0 :(得分:0)
在我的情况下,我和你一样使用id
,只显示了最后一个通知。我的解决方案很简单,为notification_id生成一个随机数:
int id = (int)(Math.random() * 101);
答案 1 :(得分:0)
是更改id
,因为它覆盖了之前的通知,因此不会打开任何内容,将其更改为:
int num = (int) System.currentTimeMillis();
manager.notify(num, builder.build())
还要更改待处理意图中的id
:
pendingIntent = PendingIntent.getActivity(this, num, mainIntent, PendingIntent.FLAG_ONE_SHOT);