Question

我有这样的数据

Brand Name  Sales Cost  Mkt
Brand1  3312    ABC
Brand2  3490    ABC
Brand3  7794    ABC
Brand4  8325    ABC
Brand5  3915    ABC
Brand6  6494    ABC

预期输出应该是这样的：

Brand Name  Sales Cost  Mkt Percentage
Brand1  3312    ABC 10%
Brand2  3490    ABC 17%
Brand3  7794    ABC 80%
Brand4  8325    ABC 89%
Brand5  3915    ABC 12%
Brand6  6494    ABC 59%

我想找出拥有ABC市场80％销售额的品牌？建议请

Answer 1

我想你想要窗口功能。我假设brandX可能会在您的数据中多次出现一个mkt（即使您的示例中没有这样的行）

select brand, 
       mkt,
       sum(sales), 
       sum(cast(sales as float))/sum(cast(sum(sales) as float)) over (partition by mkt) * 100 
from data
group by brand, mkt

dbfiddle demo

如果你想要那些拥有80％以上的人使用子查询和

select *
from
(
    select brand, 
           mkt,
           sum(sales) sumsales, 
           sum(cast(sales as float))/sum(cast(sum(sales) as float)) over (partition by mkt) * 100 percentsales
    from data
    group by brand, mkt
) t
where percentsales > 80

Answer 2

试试这个：

select * from (
select [Brand Name],
       [Sales],
       [Cost],
       [Sales]/(sum([Sales]) over (partition by (select null))) [Mkt Percentage]
from MY_TABLE
) [a] where [Mkt Percentage] >= 0.8

占T-SQL总销售额的80％

2 个答案: