我遇到了问题,当我想用nodejs,express和mysql以“梯形”形式进行查询并返回一个json时,它对我不起作用,我想要的结构是:
static_assert(std::size(U"") == 3);
static_assert(std::size(u"") == 5);
constexpr auto& test = tr<char16_t>(U""_c);
static_assert(std::is_same<decltype(test), const char16_t(&)[5]>{});
for(std::size_t i=0; i<std::size(u""); ++i) {
assert(test[i] == u""[i]);
std::cout << i << ": " << test[i] << std::endl;
}
我正在使用forEach函数,我也尝试使用回调函数。
答案 0 :(得分:0)
您需要连接所有3个表,然后遍历结果并构建嵌套对象。
var mysql = require("mysql");
var con = mysql.createConnection({
host: "localhost",
user: "yourusername",
password: "yourpassword",
database: "mydb"
});
var sql = `SELECT d.dev_id, d.dev_name, c.cont_id, c.cont_name, a.act_id, a.acti_id
FROM devices AS d
LEFT JOIN controllers AS c ON c.dev_id = c.dev_id
LEFT JOIN actions AS a ON a.cont_id = c.cont_id`;
con.connect(err => {
if (err) {
throw err;
}
conn.query(sql, (err, result, fields) => {
if (err) {
throw err;
}
var devices = {};
$result.forEach(({dev_id, dev_name, cont_id, cont_name, act_id, acti_id}) => {
devices[dev_id] = devices[dev_id] || {id: dev_id, name: dev_name, controllers: {}};
devices[dev_id].controllers[cont_id] = devices[dev_id].controllers[cont_id] || {id: cont_id, name: cont_name, actions: {}};
devices[dev_id].controllers[cont_id].actions[act_id] = {id: act_id, acti_id: acti_id};
});
});
// do something with devices here
});
请记住,所有mysql查询代码都是异步的,因此您无法正常返回值。你需要使用回调或承诺。
devices
变量如下所示:
{
devid1: {
id: "devid1",
name: "devname1",
controllers: {
contid1: {
id: "contid1",
name: "contname1",
actions: {
actionid1: {
id: "actionid1",
acti_id: "acti_id1"
},
actionid2: {
id: "actionid2",
acti_id: "acti_id2"
}
}
},
contid2: {
id: "contid2",
name: "contname2",
actions: {
actionid3: {
id: "actionid3",
acti_id: "acti_id3"
}
}
}
|
}
}