Question

嗨我有一个机器人的错误，它会工作正常一点但会返回此错误..我想知道是否有一个修复它，如果这个错误是因为代码或因为API。

Users/x/Documents/AUTOBOT/bot.js:39
    var mediaIdStr = data.media_id_string;
                          ^

TypeError: Cannot read property 'media_id_string' of undefined
at /Users/x/Documents/AUTOBOT/bot.js:39:31
at responseHandler (/Users/x/Documents/AUTOBOT/node_modules/twit/lib/oarequest.js:362:14)
at passBackControl (/Users/x/Documents/AUTOBOT/node_modules/oauth/lib/oauth.js:374:13)
at IncomingMessage.<anonymous> (/Users/x/Documents/AUTOBOT/node_modules/oauth/lib/oauth.js:386:9)
at IncomingMessage.emit (events.js:165:20)
at endReadableNT (_stream_readable.js:1101:12)
at process._tickCallback (internal/process/next_tick.js:152:19)

一旦有人提到您将在代码中看到的关键字的帐户，该机器人将工作一点然后返回该错误。这是脚本的代码..

var Twit = require('twit')
var fs = require('fs');


const dir = 'images' //Set your image folder here


var T = new Twit({
    consumer_key: 'x',
    consumer_secret: 'xx',
    access_token: 'xx',
    access_token_secret: 'xx',
    timeout_ms: 60 * 1000, // optional HTTP request timeout to apply to all requests.
})


var files = fs.readdirSync(dir);


var stream = T.stream('statuses/filter', {
    track: '@dogarchiver dog'
})

stream.on('tweet', function(tweet) {
    var file = dir + "/" + files[Math.floor(Math.random() * files.length)];

    var id = tweet['id_str'];
    var name = tweet['user']['screen_name'];
    var b64content = fs.readFileSync(file, {
        encoding: 'base64'
    })

    // first we must post the media to Twitter
    T.post('media/upload', {
        media_data: b64content
    }, function(err, data, response) {
        // now we can assign alt text to the media, for use by screen readers and
        // other text-based presentations and interpreters
        var mediaIdStr = data.media_id_string;

        var altText = ".."
        var meta_params = {
            media_id: mediaIdStr,
            alt_text: {
                text: altText
            }
        }
        T.post('media/metadata/create', meta_params, function(err, data, response) {


            // now we can reference the media and post a tweet (media will attach to the tweet)
            var params = {
                status: '@' + name,
                media_ids: [mediaIdStr],
                in_reply_to_status_id: id
            }

            T.post('statuses/update', params, function(err, data, response) {
                console.log(data)
            })

        })
    })

})

Answer 1

发生错误，Twit在回调中告诉您相关信息。你没有检查错误并假设，data将始终是一个对象。如果出现错误，则不是。

因此，您需要检查是否发生了错误并在使用data之前对其进行了适当处理。

function(err, data, response) {
    if (err) {
        console.warn("An error occurred while posting", err);
        return;
    }

    // Here you can safely access `data`

Twitter机器人自动回复图像

1 个答案: