Question

我正在使用以下函数在python中将given_dict写入csv并在下面收到以下错误。知道我做错了什么吗？

 def write_dict_as_csv(given_dict):
    ...     with open('dict.csv', 'wb') as csv_file:
    ...         writer = csv.writer(csv_file)
    ...         writer.writerow(given_dict.keys())
    ...         writer.writerows(zip(*given_dict.values()))

错误：

 >>> write_dict_as_csv(python_csv)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 2, in print_dict_as_csv
TypeError: an integer is required

使用测试用例的其他信息：

import csv
#this is a test case which is used to test the functions
def test_normalization_function():
    x1 = {'k1': 'a1', 'k2': 'b1'}
    x2 = {'k2': 'b2', 'k3': 'c2'}
    x3 = {'k1': 'a3'}
    x = [x1,x2,x3]
    y = normalization(x)
   # print('')
    for k in y:
       print('key: {} : {}'.format(k, y[k]))
    with open('mycsvfile.csv', 'wb') as f:  # Just use 'w' mode in 3.x
        w = csv.DictWriter(f, y.keys())
        w.writeheader()
        w.writerow(y)

def normalization(list_of_dict):
    super_dict = {}
    column_counter = 0
    for i_dict in list_of_dict:
        for k, v in i_dict.iteritems():
            if k not in super_dict:
                super_dict[k] = []
                for i in range(column_counter):
                    super_dict[k].append('NONE')
            super_dict[k].append(v)
        column_counter += 1
        for k in super_dict:
            if k not in i_dict:
                super_dict[k].append('NONE')
    return super_dict

运行test_normalization_function（）时代码的输出：

>>> test_normalization_function()
key: k3 : ['NONE', 'c2', 'NONE']
key: k2 : ['b1', 'b2', 'NONE']
key: k1 : ['a1', 'NONE', 'a3']
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 11, in test_normalization_function
TypeError: an integer is required

它显示字典可以打印。但是当我尝试将其保存在csv文件中时，它会出错。

将字典写入csv文件时为TypeError

0 个答案: