Question

我想让这更简单并且能够搜索变量列表：alarm1，alarm2，alarm3 ...在alarmDict.values（）

到目前为止，我的工作是：

import xml.etree.ElementTree as ET 
tree = ET.parse (path.filename) #XML file 
root = tree.getroot()


for child in root:
    alarmDict = child.attrib      #This lists the alarm codes as dicts  
    if 'alarm1' in alarmDict.values(): print ('Contains this alarm', 'alarm1')
    if 'alarm2' in alarmDict.values(): print ('Contains this alarm', 'alarm2')
    if 'alarm3' in alarmDict.values(): print ('Contains this alarm', 'alarm3')

我想要的是什么：

for child in root:
    alarmDict = child.attrib      #This lists the alarm codes as dicts
    alarm_list = [alarm1, alarm2, alarm3]  
    if alarm_list in alarmDict.values(): print ('Contains this alarm', alarm_list[])

Answer 1

你需要另一个循环：

for child in root:
    alarmDict = child.attrib      #This lists the alarm codes as dicts
    alarm_list = [alarm1, alarm2, alarm3]  
    for alarm in alarm_list:
        if alarm in alarmDict.values():
            print('Contains this alarm', alarm)

如果您想深入了解检查列表内容与其他列表的最佳方式，我建议this answer

Python 3如何在列表中搜索xml.etree.ElementTree的子节点

1 个答案: