Bizzare HttpWebResponse错误:ServerProtocolViolation

时间:2011-01-30 19:31:26

标签: c# mono httpwebrequest xamarin.ios httpwebresponse

我已尝试过所有内容,但我无法弄清楚为什么会发生此错误。

背景: 我有一个用MonoTouch编写的IPad应用程序,我有一个在后台运行的线程,每隔15秒我就会与服务器同步数据。这适用于线程的前几次迭代,但最终我得到了以下堆栈跟踪。

An exception occured: System.Net.WebException: Error getting response stream (ReadDone4): ServerProtocolViolation ---> System.FormatException: Input string was not in the correct format
  at System.UInt32.Parse (System.String s) [0x00010] in /Developer/MonoTouch/Source/mono/mcs/class/corlib/System/UInt32.cs:405 
  at System.Net.WebConnection.GetResponse (System.Byte[] buffer, Int32 max) [0x000ba] in /Developer/MonoTouch/Source/mono/mcs/class/System/System.Net/WebConnection.cs:565 
  at System.Net.WebConnection.ReadDone (IAsyncResult result) [0x00095] in /Developer/MonoTouch/Source/mono/mcs/class/System/System.Net/WebConnection.cs:446 
  --- End of inner exception stack trace ---
  at System.Net.HttpWebRequest.EndGetResponse (IAsyncResult asyncResult) [0x0005e] in /Developer/MonoTouch/Source/mono/mcs/class/System/System.Net/HttpWebRequest.cs:819 
  at System.Net.HttpWebRequest.GetResponse () [0x0000e] in /Developer/MonoTouch/Source/mono/mcs/class/System/System.Net/HttpWebRequest.cs:827 
  at SyncService.REST.RestClient.Execute[IEnumerable`1] (SyncService.REST.RestRequest request) [0x00079] in /Users/Chris/Compass/SyncService/REST/RestClient.cs:42 

我正在使用默认配置与 IIS网络服务器交谈。 这是我打电话的方法:

public RestResponse<T> Execute<T>(RestRequest request){
    var restResponse = new RestResponse<T>();
    var serializer = new JavaScriptSerializer();
    var urlPath = _baseUrl + "/" + request.Resource;
    var httpRequest = (HttpWebRequest)HttpWebRequest.Create(new Uri(urlPath));

    httpRequest.Headers = request.Headers;
    Authenticator.Authenticate(httpRequest);

    httpRequest.Method = request.Method.ToString();
    if (request.Method == Method.POST)
        SetPostData(httpRequest, request);

    HttpWebResponse httpResponse = null;
    try{
        httpResponse = (HttpWebResponse) httpRequest.GetResponse();
        var reader = new StreamReader(httpResponse.GetResponseStream());
        var responseString = reader.ReadToEnd();
        reader.Close();
        restResponse.StatusCode = httpResponse.StatusCode;
        restResponse.Headers = httpResponse.Headers;
        restResponse.Data = serializer.Deserialize<T>(responseString);
        restResponse.ResponseStatus = ResponseStatus.Completed;
    } 
    catch(WebException e){

        restResponse.ResponseStatus = ResponseStatus.Error;
        restResponse.ErrorMessage = e.Message;
        restResponse.ErrorException = e;
        var webResponse = (HttpWebResponse) e.Response;
        if (webResponse != null){
            restResponse.StatusCode = webResponse.StatusCode;
            restResponse.Headers = webResponse.Headers;
        }
        if (restResponse.StatusCode != HttpStatusCode.NotModified)
            Console.WriteLine("An exception occured: " + e + "\r\n");
    }catch (Exception ex) {
        restResponse.ResponseStatus = ResponseStatus.Error;
        restResponse.ErrorMessage = ex.Message;
        restResponse.ErrorException = ex;
    }

    if (httpResponse != null) 
        httpResponse.Close();

    return restResponse;
}

请帮忙。我不知道该怎么办。谷歌没有显示任何内容。

我可以在错误显示之前发出22个成功请求。

修改 我已将其缩小为服务器问题。这是asp.net MVC,只有在我向客户端发送304时才会发生异常。请参阅服务器代码:

private void ServeHttpStatusCode() {
    Response.StatusCode = 304;
    Response.Status = "304 Not Modified";
    Response.StatusDescription = "The resource you are requesting has not been modified";
    Response.ContentType = "application/json";
    Response.Write("{\"Error\":\"The resource you are requesting has not been modified\"}");
    Response.End();
    Response.Close();
}

2 个答案:

答案 0 :(得分:2)

  • 客户端之间是否有代理 和服务器?
  • 22次请求后总是失败吗? 该异常表示无法解析某些UInt32。
  • 您是否在服务器端获得例外?

答案 1 :(得分:1)

如果其他人在互联网上寻找这个问题的答案,我在写一些功能测试时遇到了类似的问题。他们使用http PUT将内容上传到网络服务器,然后直接使用http GET。

GET在Uint32解析中可靠地失败并出现相同的错误。 windows build很好。无奈之下,我使用Thread.Sleep(20)在http请求之间插入一些延迟,这已经清除了错误。不知道为什么,但现在可以使用,这对我的测试来说已经足够了,如果不是生产的话。