如果我在这样的列中有一堆日期时间(UTC):
63058 01/22/2018 11:00:00
63059 01/22/2018 12:00:00
63060 01/22/2018 13:00:00
Name: date, Length: 63061, dtype: object
或者这个:
DatetimeIndex(['2007-12-21 17:00:00', '2007-12-21 18:00:00',
'2007-12-21 19:00:00', '2007-12-21 20:00:00',
'2007-12-21 21:00:00', '2007-12-23 20:00:00',
'2007-12-23 22:00:00', '2007-12-23 23:00:00',
'2007-12-24 00:00:00', '2007-12-24 01:00:00',
...
'2018-01-22 04:00:00', '2018-01-22 05:00:00',
'2018-01-22 06:00:00', '2018-01-22 07:00:00',
'2018-01-22 08:00:00', '2018-01-22 09:00:00',
'2018-01-22 10:00:00', '2018-01-22 11:00:00',
'2018-01-22 12:00:00', '2018-01-22 13:00:00'],
dtype='datetime64[ns]', length=63061, freq=None)
如何将整个(列表或系列)转换为此格式:
datetime(2016, 1, 24, 18, 0, 0, tzinfo=utc)
因为我需要使用pytz
模块将utc转换为东部时间。
当我使用AttributeError: 'Index' object has no attribute 'astimezone'
原始数据格式时,我收到此错误:astimezone().strftime()
。 This is what I originally wanted to do,但现在我遇到了这个问题。感谢。
答案 0 :(得分:1)
您可以定义一个函数来转换其中一个字符串表示形式,如下所示:
from datetime import datetime
import pytz
def date_from_string(s):
"Convert ``s`` from a string to a datetime object in the UTC time zone."
dt = datetime.strptime(s, '%Y-%m-%d %H:%M:%S')
return dt.replace(tzinfo=pytz.utc)
然后您可以在构造函数
中使用map
DatetimeIndex(map(date_from_string, [
'2007-12-21 17:00:00', '2007-12-21 18:00:00',
'2007-12-21 19:00:00', '2007-12-21 20:00:00',
'2007-12-21 21:00:00', '2007-12-23 20:00:00',
'2007-12-23 22:00:00', '2007-12-23 23:00:00',
'2007-12-24 00:00:00', '2007-12-24 01:00:00',
...
'2018-01-22 04:00:00', '2018-01-22 05:00:00',
'2018-01-22 06:00:00', '2018-01-22 07:00:00',
'2018-01-22 08:00:00', '2018-01-22 09:00:00',
'2018-01-22 10:00:00', '2018-01-22 11:00:00',
'2018-01-22 12:00:00', '2018-01-22 13:00:00']),
dtype='datetime64[ns]', length=63061, freq=None)
文档有更多信息:
datetime.strptime(..)
:https://docs.python.org/2/library/datetime.html#strftime-and-strptime-behavior
map(..)
:https://docs.python.org/2/library/functions.html#map