目标是获取最接近的m3和重量数的价格并将其放在表格中。
此示例适用于我。但我硬编码m3，weight，country和transportername
查询1：
SELECT
country,
transportername,
ABS(m3-0.5) as ABS_M3 ,
m3,
ABS(weight-5) as ABS_weight,
weight,
price
FROM database.transportcost
WHERE m3 >= 0.5 AND
weight >= 5 AND
country = "GB" AND
transportername like '%aa%'
Group by transportername
Order by ABS(m3-0.5) +
ABS(weight-5) +
price
现在我想从其他表中获取硬代码值。我不知道我需要在~~xx.volumen~~和~~xx.gewicht~~中放置什么价值。
QUERY2：
INSERT INTO database.transportcostPerItem (sku,country,transportname,weight,m3,price)
SELECT g.orderitemid, p2.country, p2.transportername, p2.weight, p2.m3, p2.price
FROM database.orderitem g
JOIN database.order i on i.orderid = g.orderid
JOIN database.matrixtable xx on g.orderitemid = xx.sku
JOIN database.vlog cc on i.orderid = cc.orderid
JOIN
(
SELECT *
FROM database.transportcost
Group by transportername
Order by ABS(m3-~~xx.volumen~~) +
ABS(weight-~~xx.gewicht~~) +
price
) as p2 on p2.country = i._country AND
p2.transportername = cc._transportername AND
p2.weight = xx.gewicht AND
p2.m3 = xx.volumen
;
编辑：
示例数据
Table: database.transportcost country | transportername | m3 | weight | price --------+-----------------+--------+--------+-------- GB | aa | 50.00 | 50 | 77.70 GB | bb | 0.50 | 125 | 83.19 GB | cc | 0.50 | 125 | 96.03 GB | bb | 0.60 | 150 | 83.19 GB | aa | 75.00 | 75 | 89.04 GB | cc | 0.60 | 150 | 96.03 GB | dd | 50.00 | 50 | 163.38 GB | cc | 0.70 | 175 | 96.03 GB | bb | 0.70 | 175 | 96.85 GB | ee | 0.53 | 175 | 102.78 GB | gg | 0.53 | 175 | 110.37 GB | aa | 100.00 | 100 | 89.04 GB | cc | 0.80 | 200 | 96.03 GB | bb | 0.80 | 200 | 96.85 GB | ff | 0.60 | 200 | 110.33 DE | aaa | 0.50 | 50 | 26.40 DE | bbb | 0.50 | 75 | 31.84 DE | aaa | 0.75 | 75 | 34.19 DE | ccc | 0.50 | 100 | 34.17 DE | bbb | 0.67 | 100 | 35.47 DE | ccc | 1.00 | 100 | 37.59 DE | ddd | 0.50 | 100 | 62.38 DE | ccc | 0.63 | 125 | 43.04 DE | bbb | 0.83 | 125 | 44.24 DE | aaa | 0.93 | 125 | 45.84 DE | eee | 0.50 | 125 | 53.80 DE | fff | 0.50 | 125 | 54.02国家
Query 1 的 GB结果
country | transportername | ABS_M3 | m3 | ABS_weight | weight | price --------+-----------------+-----------------------+-------+------------+--------+------- GB | aa | 49.5 | 50.00 | 45 | 50 | 77.70 GB | bb | 0 | 0.50 | 120 | 125 | 83.19 GB | cc | 0 | 0.50 | 120 | 125 | 96.03 GB | dd | 49.5 | 50.00 | 45 | 50 | 163.38 GB | ee | 0.030000000000000027 | 0.53 | 170 | 175 | 102.78 GB | gg | 0.030000000000000027 | 0.53 | 170 | 175 | 110.37国家
Query 1 的 DE结果
country | transportername | ABS_M3 | m3 | ABS_weight | weight | price --------+-----------------+--------+------+------------+--------+------- DE | aaa | 0 | 0.50 | 45 | 50 | 26.40 DE | bbb | 0 | 0.50 | 70 | 75 | 31.84 DE | ccc | 0 | 0.50 | 95 | 100 | 34.17 DE | ddd | 0 | 0.50 | 95 | 100 | 62.38 DE | eee | 0 | 0.50 | 120 | 125 | 53.80 DE | fff | 0 | 0.50 | 120 | 125 | 54.02 DE | ggg | 0 | 0.50 | 195 | 200 | 87.29
最终Query 2的结果应如下所示：
Table: database.transportcostPerItem orderitemid | country | transportername | m3 | weight | price ------------+---------+-----------------+-----+--------+------ 1 | GB | aa | 0,5 | 5 | 77.70 2 | DE | aaa | 0,5 | 5 | 26.40
答案 0 :(得分：1)
看来你只是在寻找最便宜的运输给定的m3和重量。在第一步中，您将找到至少m3和重量的所有运输。其中你选择最低的价格。
select *
from transportcost
where country = 'GB'
and m3 >= 0.5
and weight >= 5
order by price
limit 1;
如果你想要最接近你给定的m3和重量的测量，即使那个传输更贵，你可以按百分比的总和来订购：
select *
from transportcost
where country = 'GB'
and m3 >= 0.5
and weight >= 5
order by m3 / 0.5 + weight / 5, price
limit 1;
现在，不是给定m3，权重，国家/地区和运输商名称，而是从订单明细表中获取值。如果这只是一个订单详细记录，那么方法将完全相同，而不是与固定值（m3 >= 0.5）进行比较，而是与订单明细记录的值（transportcost.m3 >= orderdetail.m3）进行比较。唉，有多个订单详细信息记录，这种方法不再起作用，因为我们不能将结果限制为一行，而是每个订单详细记录需要一行。这可以通过标准SQL中的窗口函数（ROW_NUMBER，RANK等）或横向连接（CROSS APPLY）来解决。 MySQL既没有。
以下是加入运输成本表的方法：
select *
from <your order tables>
join transportcost tc
where tc.country = i._country
and tc._transportername = cc._transportername
and tc.m3 >= xx.volumen
and tc.weight >= xx.gewicht;
现在，您必须找到一种方法对结果进行排名，以便只为每个订单详细信息获得最佳匹配。一种方法是使用变量模拟ROW_NUMBER。您可能希望在其他答案中查找此内容。另一个是SELECT clause中的限制子查询，但为此，您需要一个列来标识传输成本表中的记录。假设您添加了一个名为ID的列，并使用唯一值填充...
select <some order columns>, tc.*
from
(
select <some order columns>,
(
select id
from transportcost tc
where tc.country = i._country
and tc._transportername = cc._transportername
and tc.m3 >= xx.volumen
and tc.weight >= xx.gewicht
order by tc.m3 / xx.volumen + tc.weight / xx.gewicht, tc.price
limit 1
) as best_transportcost_id
from <your order tables>
) data
join transportcost tc
where tc.id = data.best_transportcost_id;
（您可以通过连接值以某种方式在没有ID的情况下执行此操作，例如'GB-aa-50.00-50-77.70'，以便有一个标识运输成本记录的字符串，但我不建议这样做。最好有一个带有快速查找索引的唯一ID。更好的方法是使用更好的DBMS： - ）
答案 1 :(得分：0)
我使用了@Thorsten的解决方案。
这是结果
INSERT INTO database.transportcostperitem (transportcostID, orderID, sku, country, transportername, weight, m3,price,shippingmethod,shippingstatus,shippingDate)
SELECT
transportcostID,
orderID,
sku,
_country,
transportername,
transportTmp._weightReal,
transportTmp._m3 ,
price,
_shippingMethod,
_shippingStatus,
_shippingDate
FROM(
SELECT
b.orderID,
o.sku,
b.transporter,
o._country,
i._shippingMethod,
i._shippingStatus,
i._shippingDate,
o._m3,
o._weightReal,
(
SELECT id
FROM database.transportcost tc
where
tc.transportername = b._transporterName AND
tc.country = o._country AND
tc.weight >= o._weightReal AND
tc.m3 >= o._m3
order by o._m3 / tc.m3 + o._weightReal / tc.weight , tc.price
limit 1
) as transportcostID
FROM database.orderitem o
JOIN database.order i on i.orderID = o.orderID
JOIN database.vlog b on b.orderID = o.orderID
WHERE sku >0
)as transportTmp
JOIN database.transportcost tc
where tc.id = transportcostID AND
_shippingMethod is not null
orderID by sku
;