我有单个延迟加载模块,其中多个组件具有动态路由,每个组件由路由器保护定义。因此,如何为具有动态路由的每个组件配置路由。对于每个路径路径,我能够看到相同的组件,当我使用url手动路由时,我收到错误“Guard不是一个函数”。
以下是我的代码: mycomponent.module.ts
@NgModule({
imports: [
routing,
SharedModule,
CommentsModule,
],
declarations: [
MyComponent1,
MyComponent2,
MyComponent3,
MyComponent4,
MyComponent5,
],
providers: [mycomponentService]
})
export class MyComponentModule { }
mycomponent.routing.ts
const routes: Routes = [
{
path: '',
canActivate: [AuthGuard],
canActivateChild: [AuthGuard],
children: [
{ path: '/my-todos', component: MyComponent1 },
{ path: '/edit-my-todo/:tid', component: MyComponent2 },
{ path: '/edit-my-todo/single-todo/:tid', component: MyComponent2 },
{ path: '/edit-my-todo/multi-todo/:tid', component: MyComponent2 },
{ path: '/add-todo', component: MyComponent3 },
{ path: '/multiple-todo-details/:tid', component: MyComponent4 },
{ path: '/todo/:alias', component: MyComponent5 },
{ path: '/todo-preview/:tid', component: MyComponent5 },
]
},
];
app.routing.ts
{
path: '',
loadChildren:'app/mycomponent/mycomponent.module#MyComponentModule'
};
如何为这条动态路线配置路线,即使我面临gaurd错误也不是一个功能。有谁知道如何配置上面的路线。以前是否有人面临同样的问题。任何帮助都会有很大的帮助。提前感谢您的帮助。
答案 0 :(得分:2)
我想通了,配置路线的方式。希望这有助于将来的某个人
mycomponent.routing.ts
const routes: Routes = [
{ path: 'my-todos', component: MyComponent1 },
{ path: 'edit-my-todo/:tid', component: MyComponent2 },
{ path: 'edit-my-todo/single-todo/:tid', component: MyComponent2 },
{ path: 'edit-my-todo/multi-todo/:tid', component: MyComponent2 },
{ path: 'add-todo', component: MyComponent3 },
{ path: 'multiple-todo-details/:tid', component: MyComponent4 },
{ path: 'todo/:alias', component: MyComponent5 },
{ path: 'todo-preview/:tid', component: MyComponent5 },
];
app.routing.ts
{
path: '',
canActivate: [AuthGuard],
canActivateChild: [AuthGuard],
children: [
{ path: '',
loadChildren:
'app/mycomponent/mycomponent.module#MyComponentModule'
},
],
}
这项工作正常,运作良好。