Question

我们正在尝试使用PHP连接到我们的本地mysql数据库。我们故意遗漏了密码，但是它是正确的。但是，这不起作用，我们不断收到以下错误消息：警告：mysqli_connect（）期望参数5为long，字符串为。

指的是第7行@Override public void onCreateOptionsMenu(Menu menu, MenuInflater inflater) { super.onCreateOptionsMenu(menu, inflater); menu.clear(); inflater.inflate(R.menu.menu_search_view_explore_ideas, menu); SearchManager searchManager = (SearchManager) getActivity().getSystemService(Context.SEARCH_SERVICE); searchView = (SearchView) menu.findItem(R.id.action_search).getActionView(); searchView.setQueryHint("Search..."); ((EditText) searchView.findViewById(android.support.v7.appcompat.R.id.search_src_text)).setTextColor(Color.WHITE); ((EditText) searchView.findViewById(android.support.v7.appcompat.R.id.search_src_text)).setHintTextColor(getResources().getColor(R.color.notify_user_color)); if (searchManager != null) { searchView.setSearchableInfo( searchManager.getSearchableInfo(getActivity().getComponentName())); } AutoCompleteTextView searchTextView = searchView.findViewById(android.support.v7.appcompat.R.id.search_src_text); try { Field mCursorDrawableRes = TextView.class.getDeclaredField("mCursorDrawableRes"); mCursorDrawableRes.setAccessible(true); mCursorDrawableRes.set(searchTextView, R.drawable.cursor_for_search_view); //This sets the cursor resource ID to 0 or @null which will make it visible on white background } catch (Exception e) { } searchView.setOnQueryTextListener(new SearchView.OnQueryTextListener() { @Override public boolean onQueryTextSubmit(String query) { mAdapter.getFilter().filter(query); return true; } @Override public boolean onQueryTextChange(String newText) { mAdapter.getFilter().filter(newText); return true; } }); }

$conn = mysqli_connect($servername, $port, $uname, $pword, $dbname);

我们的confiq.php文件

<?php
$servername = "Mysql@127.0.0.1";
$port = "3306";
$uname = "root@localhost";
$pword = "1234";
$dbname = "database";
$conn = mysqli_connect($servername, $port, $uname, $pword, $dbname);
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}
?>

Answer 1

构造函数

中的args顺序错误

$conn = mysqli_connect($servername, $port, $uname, $pword, $dbname);
 should be 
$conn = mysqli_connect($servername, $uname, $pword, $dbname, $port );

但是看起来配置文件中的信息不正确 -

define('DB_HOST', 'Mysql@127.0.0.1');

我怀疑，

实际上是

define('DB_HOST', '127.0.0.1');

虽然也许不是！

然后，使用配置文件中的信息，连接将是：

$conn = mysqli_connect( DB_HOST, DB_USER, DB_PASSWORD, DB_NAME, port );

如何使用PHP连接到本地MySql数据库。

1 个答案: