Question

我有2个不同模型的2个查询集，如下所示：

qs1=[[username1, lastname1, firstname1], [username2, lastname2, firstname2]........[username10, lastname10, firstname10]]
qs2=[[username1, email1], [username2, email2]...[username10, email10]]

我需要将它们合并为一个并按用户名排序。所以它变成了这样：

qs=[[username1, lastname1,  firstname1, email1], [username2, lastname2,  firstname2, email2]...[username10, lastname10,  firstname10, email10]]

qs1和qs2是具有多个条目的查询集。

我在view.py中有代码：

usernames = C.objects.values('username')
for username in usernames:
    try:
       qs1=A.objects.filter(username=username).values('username','lastname',' 'firstname')
       qs2=B.objects.filter(username=username).values('username','email')

qs = sorted(chain(qs1, qs2))
return qs

如何将qs1和qs2组合到qs？

Answer 1

使用itertools

from itertools import chain
result_list = list(chain(qs1, qs2))

合并两个查询集

1 个答案: