java simple if语句没有正确评估

Question

知道为什么这不起作用？下面的实际代码和调试器的运行时间图，如果语句应该设置变量Testnumber = 1;但是当它被评估时它是= 0 ?????

private String Convert2Time(int Number){
    int  Hours, Minutes, HrsRemainder, MinRemainder, Seconds; String RetString, OneString, TwoString, ThreeString, HoursStr, MinStr, SecStr;
    byte Testnumber = 0;
    Hours = Number / 3600;
    HrsRemainder = Number % 3600;
    Minutes = HrsRemainder / 60;
    MinRemainder = HrsRemainder % 60;
    Seconds = MinRemainder / 1;

    HoursStr = Integer.toString(Hours);
    MinStr = Integer.toString(Minutes);
    SecStr = Integer.toString(Seconds);
    ThreeString = HoursStr + " Hrs " + MinStr + " Min " + SecStr + " Sec";
    TwoString = MinStr + " Min " + SecStr + " Sec";
    OneString = SecStr + " Sec";
    if (Hours < 0){
        Testnumber = 2;
    } else {
        if (Minutes < 0){
            Testnumber = 1;
        }
    }
    switch (Testnumber){
        case 2:
            RetString = ThreeString;
            break;
        case 1:
            RetString = TwoString;
            break;
        default:
            RetString = OneString;
    }
    return RetString;
}

Code from debugger

Answer 1

根据您的输出，Hours < 0和Minutes < 0都评估为false。没有理由设置TestNumber = 1;甚至TestNumber = 2;。它距离0

byte Testnumber = 0;

Answer 2

在阅读完您的方法后，您似乎希望将秒数转换为可读时间。

主要问题是条件。小时，分钟，秒将始终具有有效的更大或等于零，它们不会是负数。因为你正在划分正数。

因此private float RoundToNearestEven(float input){ // if no decimal type make it even if(input % 1 == 0) { if(input % 2 != 0) { // arbitrary add 1 return input + 1; } // already even return input; } bool isPositive = (input > 0); float absInput = Mathf.abs(input) float roundedInput = Mathf.Round(absInput); if(isPositive && roundedInput % 2 == 0) { return roundedInput; } else { return -roundedInput; } // was rounded up if(isPositive && input % 1 > .5) { return roundedInput - 1; } else if (isPositive && input % 1 < .5) { //was rounded down return roundedInput + 1; } else if (input % 1 > .5) { //negative and was rounded up return -(roundedInput - 1); } else { return -(roundedInut + 1); } ， private int round_to_even(float input){return Mathf.Round(input / 2.0) * 2; } 等任何条件都不会返回true; 你需要反转它们。因为只有在有任何小时，分钟，秒时，您才希望在响应中添加正确的块。

Hours < 0

Answer 3

因为您不必要地使代码复杂化。不要重新发明轮子。使用现有的Java类为您完成工作：

int numInSeconds = 61;
int millis = numInSeconds * 1000;
Date time = new Date(millis);

int hours = time.getHours();
int mins = time.getMinutes();
int secs = time.getSeconds();

StringBuilder builder = new StringBuilder();
if (hours > 0) {
    builder.append(hours);
    builder.append(" hrs ");
}
// etc.
String displayTime = builder.toString(); // "1 mins 1 secs"