我想在使用skyscreamer比较两个JSON文件时排除某些JSON属性。
测试文件1:
{
"Name":"test1",
"addressList":[
{
"street":"123 fake street",
"postalcode":"33344"
},
{
"street":"99 street avn",
"postalcode":"23434"
},
{
"street":"900 street city",
"postalcode":"45100"
}
]
}
测试文件2:
{
"Name":"test1",
"addressList":[
{
"street":"123 fake street",
"postalcode":"33344"
},
{
"street":"88 abc street",
"postalcode":"23434"
},
{
"street":"900 street city",
"postalcode":"45100"
}
]
}
如何通过排除addressList.street属性来比较上面的JSON文件?
答案 0 :(得分:0)
我们可以使用CustomComparator并根据需要编写自己的自定义比较器
org.skyscreamer.jsonassert.Customization
org.skyscreamer.jsonassert.comparator.CustomComparator
示例:
compareJSON(expected, actual, new CustomComparator(JSONCompareMode,new Customization(addressList.street,(o1, o2) -> true)))