Question

我已经打了一段时间了

我有一个表格，其中包含我使用以下查询创建的重复位置;

select * from Table A where location in
(select location from Table A
group by location having count(*) >1);

重复的位置应该具有与之关联的相同代码。如果复制的位置与其他位置的代码不同，那么我想选择它们是哪些

我有这个示例表

Table A
code    location
111     x12345
111     x12345
222     y12346
222     y12346
111     y12346
222     z12348
333     z12348
333     r12340
333     r12340

我想选择具有不同代码的所有重复位置。例如，输出应该如下所示

code    location
222     y12346
222     y12346
111     y12346
222     z12348
333     z12348

Answer 1

您可以使用an analytic count()获取每个位置使用的代码数量：

select code, location,
  count(distinct code) over (partition by location) as cnt
from TableA

然后将其用作子查询，过滤该计数为＆gt; 1：

select code, location
from (
  select code, location,
    count(distinct code) over (partition by location) as cnt
  from TableA
)
where cnt > 1;

      CODE LOCATION
---------- --------
       111 y12346  
       222 y12346  
       222 y12346  
       222 z12348  
       333 z12348

Answer 2

另一种（虽然不是更好）选项，没有分析：

SQL> with tableA (code, location) as
  2  (select 111, 'x12345' from dual union
  3   select 111, 'x12345' from dual union
  4   select 222, 'y12346' from dual union
  5   select 222, 'y12346' from dual union
  6   select 111, 'y12346' from dual union
  7   select 222, 'z12348' from dual union
  8   select 333, 'z12348' from dual union
  9   select 333, 'r12340' from dual union
 10   select 333, 'r12340' from dual
 11  )
 12  select code, location
 13  from tableA
 14  where location in (select location from tableA
 15                     group by location
 16                     having count(distinct code) > 1);

      CODE LOCATI
---------- ------
       333 z12348
       222 z12348
       222 y12346
       111 y12346

SQL>

在一列中查找在另一列中具有不同代码/ ID的重复项

2 个答案: