Question

我做了一个工作线程任务，另一个是我的公共第三方功能。我想同时运行线程插槽（例如：StartWork（））和我的公共函数（例如：on_pushButton_4_clicked（）），但它们不会。请告诉我如何做到这一点。这是我的代码：

Mythread.cpp

#include "mythread.h"
#include "ui_mythread.h"
Mythread::Mythread(QWidget *parent) :
    QWidget(parent),
    ui(new Ui::Mythread)
{
    ui->setupUi(this);
    //Debug
    this->dumpObjectInfo();
    //myWorker->dumpObjectInfo();
}

Mythread::~Mythread()
{
    myWorker->abort();
    WorkerThread->wait();
    qDebug()<<"Deleting thread and worker in Thread "<<this->QObject::thread()->currentThreadId();
    delete WorkerThread;
    delete myWorker;
    delete ui;
}
void Mythread::on_pushButton_2_clicked()
{
    qDebug() << "stopwork signal emmitted";
    emit stopWorkSignal();
}

void Mythread::on_pushButton_4_clicked()
{
    myWorker = new worker;
    WorkerThread = new QThread;
    myWorker->moveToThread(WorkerThread);
    WorkerThread->start();

    connect(myWorker, SIGNAL(valueChanged(QString)),this, SLOT(myfunc(QString)));
    connect(WorkerThread, SIGNAL(started()), myWorker, SLOT(StartWork()));
    connect(this, SIGNAL(stopWorkSignal()), myWorker, SLOT(abort()));
    qDebug()<<"inside work";
    int i =0;
    while (i<1000)
    {
    qDebug()<<":count *i=========>"<<i;
    i++;
    }
    return;
}

void Mythread::myfunc(QString s)
{
    qDebug()<<"thread TXT"<<s;
    //
    ui->label->setText(s);
}

worker.cpp

#include "worker.h"
#include<QDebug>
#include<mythread.h>

worker::worker(QObject *parent) :
    QObject(parent)
{
    _working =false;
    _abort = false;
}

void worker::do_Work()
{
    qDebug() << "inside do Work";
    qDebug()<<"Starting worker process in Thread   "<<thread()->currentThreadId();
    for (int i = 1; i<100; i ++) {
    // Checks if the process should be aborted
    mutex.lock();
    bool abort = _abort;
    mutex.unlock();
    if (abort) {
        qDebug()<<"Aborting worker process in Thread "<<thread()->currentThreadId();
        break;
    }

    // This will stupidly wait 1 sec doing nothing...
    QEventLoop loop;
    loop.processEvents(QEventLoop::AllEvents);
    QTimer::singleShot(100, &loop, SLOT(quit()));
    loop.exec();

     //Once we're done waiting, value is updated
    emit valueChanged(QString("%1").arg(i++));
    }

    mutex.lock();
    _working = false;
    mutex.unlock();

    qDebug()<<"Worker process finished in Thread "<<thread()->currentThreadId();
    emit finished();
}


void worker::abort()
{
    qDebug()<<"Stop Thread";
    mutex.lock();
    if (_working) {
    _abort = true;
    qDebug()<<"Request worker aborting in Thread "<<thread()->currentThreadId();
    }
    mutex.unlock();
    emit finished();
    //lbl->close();
    //lbl->deleteLater();
}
void worker::StartWork()
{
    qDebug() << "inside StartWork";
    _working = true;
    _abort = false;

    //emit running();
    do_Work();
}

输出如下：

  :count *i=========> 988 
  :count *i=========> 989 
  :count *i=========> 990 
  :count *i=========> 991 
  :count *i=========> 992 

 thread TXT "1" 
 thread TXT "3" 
 thread TXT "5" 
 thread TXT "7"

Answer 1

一些问题：

您启动线程后，您将QThread :: started连接到StartWork（），，因此您可能会错过信号。
做一个1000的while（）循环是在很短的时间内完成的，所以很有可能它会在你有机会向另一个线程发出信号之前运行。
最重要的问题是，当您在线程上发出valueChanged（）时，它将排队到myFunc（）上的主线程。

你总是可以调用QThread :: currentThread（）来查看它是否在正确的线程上运行，它也是操作系统的UP来安排你的线程所以期望看到两个线程的输出不可能同时发生你想要的方式。

如何在第三方函数调用之前运行线程？

1 个答案: