我有这种字典:
const recommendations =
{ '014A8C3D-FE99-4DE3-9F9F-F197A3CB270F':
{ zL: 0.0402632597754549,
zD: 0,
mL: 2,
mD: 0,
rate: 0.02013162988772745 },
'036EA860-FDF1-40DA-8915-A2F02241DC7D':
{ zL: 0.0297356539387,
zD: 0,
mL: 1,
mD: 0,
rate: 0.0297356539387 },
'4A49B2C5-62A6-494B-BE77-FBEF5C102579':
{ zL: 0.052390243902439025,
zD: 0,
mL: 1,
mD: 0,
rate: 0.052390243902439025 },
'640674E4-5080-4BFD-983F-330D1C9150D0':
{ zL: 0.011376894745,
zD: 0,
mL: 1,
mD: 0,
rate: 0.011376894745 }
}
每个键都是“推荐标识符”,每个值都是推荐属性的字典。
我想获得一系列推荐ID,按'rate'属性(降序)排序:
//sortedRecommendations
['4A49B2C5-62A6-494B-BE77-FBEF5C102579',
'036EA860-FDF1-40DA-8915-A2F02241DC7D',
'014A8C3D-FE99-4DE3-9F9F-F197A3CB270F',
'640674E4-5080-4BFD-983F-330D1C9150D0']
我想我应该首先将我的字典(不可排序)转换为数组(可排序)。但后来我找不到获得预期结果的方法......
答案 0 :(得分:4)
您可以通过获取比较属性的增量来按rate
属性降序排序。
var recommendations = { '014A8C3D-FE99-4DE3-9F9F-F197A3CB270F': { zL: 0.0402632597754549, zD: 0, mL: 2, mD: 0, rate: 0.02013162988772745 }, '036EA860-FDF1-40DA-8915-A2F02241DC7D': { zL: 0.0297356539387, zD: 0, mL: 1, mD: 0, rate: 0.0297356539387 }, '4A49B2C5-62A6-494B-BE77-FBEF5C102579': { zL: 0.052390243902439025, zD: 0, mL: 1, mD: 0, rate: 0.052390243902439025 }, '640674E4-5080-4BFD-983F-330D1C9150D0': { zL: 0.011376894745, zD: 0, mL: 1, mD: 0, rate: 0.011376894745 } },
keys = Object
.keys(recommendations)
.sort((a, b) => recommendations[b].rate - recommendations[a].rate);
console.log(keys);

答案 1 :(得分:2)
这很有效。
const recommendations =
{ '014A8C3D-FE99-4DE3-9F9F-F197A3CB270F':
{ zL: 0.0402632597754549,
zD: 0,
mL: 2,
mD: 0,
rate: 0.02013162988772745 },
'036EA860-FDF1-40DA-8915-A2F02241DC7D':
{ zL: 0.0297356539387,
zD: 0,
mL: 1,
mD: 0,
rate: 0.0297356539387 },
'4A49B2C5-62A6-494B-BE77-FBEF5C102579':
{ zL: 0.052390243902439025,
zD: 0,
mL: 1,
mD: 0,
rate: 0.052390243902439025 },
'640674E4-5080-4BFD-983F-330D1C9150D0':
{ zL: 0.011376894745,
zD: 0,
mL: 1,
mD: 0,
rate: 0.011376894745 }
};
var recommendationkeys = Object.keys(recommendations);
recommendationkeys.sort(function(first,second){
return recommendations[second].rate - recommendations[first].rate;
});
console.log(recommendationkeys);
答案 2 :(得分:1)
Object.keys(recommendations).sort((a, b) => ( recommendations[a].rate < recommendations[b].rate ? -1 : 1)); //asc
Object.keys(recommendations).sort((a, b) => ( recommendations[a].rate < recommendations[b].rate ? 1 : -1)); //desc
编辑:a.rate确实是未定义的。建议并[a] .rate