Question

我试图创建一个字典（我认为这是最好的选择......）来设置一种地址簿。想法是返回像

这样的东西

contacts = {"Bruce Wayne":{"phone number":'123-456-7890', "car":"All of them"}, "Alfred":{"phone number" :'987-654-3210', "car": "limo"}, "Clark Kent":{"phone number":'951-753-8520', "car":"None, flying works."}}

这很有效。我可以说console.log(contacts["Bruce Wayne"])并返回：

{＆＃39;电话号码＆＃39;：＆＃39; 123-456-7890＆＃39;，car：＆＃39;所有人＆＃39; }

正确返回<{p}}

123-456-7890

但是，我无法弄清楚如何遍历每个人，然后是每个人console.log(contacts["Bruce Wayne"]["phone number"])和phone number。

使用此：

car

只返回

[object Object]
  [对象]
  [object Object]

我试图获得（伪代码）

for (const[key, value] of Object.entries(contacts)){
    console.log(contacts[key]);
}

布鲁斯·韦恩，电话号码是123-456-7890，车就是所有人阿尔弗雷德，电话号码是987-654-3210，车是豪华轿车

编辑：我也试过了

[First key], [key] is [value], [key] is [value]

也返回for (var person in contacts){ console.log(contacts[person]) } ...

Answer 1

试试这个：

for (let i in contacts) {
    console.log(i + ',' + JSON.stringify(contacts[i]).replace(/\":\"/g, ' is ').replace(/["{}]/g, ''));
}

或

let contacts = { "Bruce Wayne": { "phone number": '123-456-7890', "car": "All of them" }, "Alfred": { "phone number": '987-654-3210', "car": "limo" }, "Clark Kent": { "phone number": '951-753-8520', "car": "None, flying works." } }

function consoleObj(obj, separator, attrIntro) {
    let result = '';

    for (let name in obj) {
        result += name + separator;
        for (let attr in obj[name]) {
            result += attr + attrIntro + obj[name][attr] + separator;
        }
        result += '\n';
    }

    return result;
}


console.log(consoleObj(contacts, ',', ' is '));

或者

function consoleObj(obj, separator, attrIntro) {
    return Object.keys(obj).reduce(function(result, name) {
        result += name + separator;
        Object.keys(obj[name]).forEach(function(attr) {
            result += attr + attrIntro + obj[name][attr] + separator;
        });
        result += '\n';
        return result;
    }, '');
}
console.log(consoleObj(contacts,',',' is '));

Answer 2

您的for..of循环为您提供了包含属性的名称和对象，因此您需要更改访问"phone number"和"car"到details['phone number']等的方式。

const contacts = {"Bruce Wayne":{"phone number":'123-456-7890', "car":"All of them"}, "Alfred":{"phone number" :'987-654-3210', "car": "limo"}, "Clark Kent":{"phone number":'951-753-8520', "car":"None, flying works."}}

// join an object
const joinObject = (obj, glue = 'is', joiner = ', ') => 
  Object.keys(obj)
    .map(k => `${k} ${glue} ${obj[k]}`)
    .join(joiner)

// fixed string
for (const [name, details] of Object.entries(contacts)) {
  console.log(`${name}, phone number is ${details['phone number']}, car is ${details['car']}`);
}

// dynamic property description
for (const [name, details] of Object.entries(contacts)) {
  console.log(name + ' ' + joinObject(details))
}

循环播放＆＃39; layered＆＃39; javascript字典

2 个答案: