Question

我希望能够为“前3个城市”，“下3个城市”，“前3个项目类别”和“下3个项目类别”打印3个元组（列表中）的元素。但是，我现在唯一能做的就是打印出每个元组，但这不是我真正想要的。

purchases.txt

    public void CallButtonFromAnotherRibbon()
    {
        try
        {
            SendKeys.Send("%");
            SendKeys.Send("Y");
            SendKeys.Send("2");
            SendKeys.Send("%");
            SendKeys.Send("Y");
            SendKeys.Send("7");
        }
        catch (Exception ex)
        {
            MessageBox.Show(ex.ToString(), "Unexpected Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
        }
    }

test.py

library(readr)
library(dplyr)
library(tidyr)
library(ggplot2)

Ind <- read_csv("Industrial.csv")

Ind1 <- Ind %>%
  select(Period,Year,City,Sub_Market,GeoLevel7,Property_Type,Average_Equivalent_Yield_Prime_Grade) %>%
  filter(Sub_Market == "Sydney Metro" & GeoLevel7 == "South Sydney" & Property_Type == "Distribution Warehouse/Logistics")%>%
  unite(Time,Period,Year,sep=".")

ggplot(data=Ind1, aes(x=Time, y=Average_Equivalent_Yield_Prime_Grade,group=1)) +
  geom_line(color="#aa0022", size=1) +
  geom_point(color="#aa0022", size=1) +
  scale_x_discrete(breaks=c("Q1.1976","Q1.1981","Q1.1986","Q1.1991","Q1.1996","Q1.2001","Q1.2006","Q1.2011","Q1.2016","Q1F.2021","Q1F.2026")) +
  ggtitle("South Sydney Cap Rates") +
  labs(x="", y="(%)") +
  theme(axis.title.y = element_text(size=12, family="Times", color="#666666")) +
  theme(axis.text = element_text(size=12, family="Times")) +
  theme(plot.title = element_text(size=14, family="Times", face="bold", hjust=0, color="#666666")

我的输出

2012-01-01  09:00   San Jose    Men's Clothing  214.05  Amex
2012-01-01  09:00   Fort Worth  Women's Clothing    153.57  Visa
2012-01-01  09:00   San Diego   Music   66.08   Cash
2012-01-01  09:00   Pittsburgh  Pet Supplies    493.51  Discover
2012-01-01  09:00   Omaha   Children's Clothing 235.63  MasterCard
2012-01-01  09:00   Stockton    Men's Clothing  247.18  MasterCard
2012-01-01  09:00   Austin  Cameras 379.6   Visa
2012-01-01  09:00   New York    Consumer Electronics    296.8   Cash
2012-01-01  09:00   Corpus Christi  Toys    25.38   Discover
2012-01-01  09:00   Fort Worth  Toys    213.88  Visa

所需的输出

f = open("purchases.txt")

def separator():
      str = ("="*48)
      print (str)
      return;
   citydict = {}
   catdict = {}
    strmoney=line.split('\t')[4]
      money = float(strmoney)

      if city not in citydict:
         citydict[city] = 0
      citydict[city] += money
      if item not in catdict:
         catdict[item] = 0
      catdict[item] += money   

top3citylist = sorted(citydict.items(),key=lambda x:-x[1])[:3]
   top3catlist = sorted(catdict.items(),key=lambda x:-x[1])[:3]

   bottom3citylist = sorted(citydict.items(),key=lambda x:x[1])[:3]
   bottom3catlist = sorted(catdict.items(),key=lambda x:x[1])[:3]

print("Top Three Cities \n")
      separator()

      for i in top3citylist:

         print (i)

      separator()


      print("Bottom Three Cities \n")
      separator()

      print (bottom3citylist[2])
      print (bottom3citylist[1])
      print (bottom3citylist[0])

      separator()

      print ("\nThe Average Sales from " + str(len(catlist))+ " Item Categories:\n\t\t\t\t\t {:0.2f}".format(avritem))

      print("Top Three Item Categories")
      separator()

      for i in top3catlist:

         print (i)

      separator()


      print("\nBottom Three Item Categories")
      separator()


      print (bottom3catlist[2])
      print (bottom3catlist[1])
      print (bottom3catlist[0])

      separator()      

f.close()

Answer 1

你的问题

print (i)

其中i是元组。元组中的默认__str__方法将通过调用每个项目上的str来打印括号中的内容（因此调用每个项目的__str__方法。

您的separator()来电正在打印一段我们可以定义为len_sep的行。我们需要该值，以便能够分隔元组中的项目并满足=生成的字符串（separator()符号链）的结尾。我们还假设您的元组总是有2个值。打印两个项目并将它们分开的代码......

for name, value in i:
    str_val = str(value)
    len_space = len_sep - len(name) - len(str_val)
    print('{}{}{}'.format(name, ' ' * len_space, str_val))

当然，您必须提供代码中未提供的len_sep值。

Answer 2

我解决了！我所要做的就是改变

  for i in top3citylist:

     print (i)

这样的事情

for i in top3citylist:

     print("{0:<29}{1:>18}".format(i[0],i[1]))

在元组中打印元素，不带逗号，引号和括号

2 个答案: