Question

多项选择测试如何将正确的计数变量发送到数组分数[8] ... 例如。该密钥用于扫描数组答案并得到7第一行，但现在我如何更新7到数组得分[0]。该程序正在运行，我只需要知道如何正确更新阵列得分，以便我能找到平均感谢

#include <iostream>
#include <string>

using namespace std;

int main()
{
    const int NUMBER_OF_STUDENTS = 8;
    const int NUMBER_OF_QUESTIONS = 10;
    int score[8];
    string studentnames[8];
    double avg;

    // Students' answers to the questions
    char answers[NUMBER_OF_STUDENTS][NUMBER_OF_QUESTIONS] =
    { { 'A', 'B', 'A', 'C', 'C', 'D', 'E', 'E', 'A', 'D' },
    { 'D', 'B', 'A', 'B', 'C', 'A', 'E', 'E', 'A', 'D' },
    { 'E', 'D', 'D', 'A', 'C', 'B', 'E', 'E', 'A', 'D' },
    { 'C', 'B', 'A', 'E', 'D', 'C', 'E', 'E', 'A', 'D' },
    { 'A', 'B', 'D', 'C', 'C', 'D', 'E', 'E', 'A', 'D' },
    { 'B', 'B', 'E', 'C', 'C', 'D', 'E', 'E', 'A', 'D' },
    { 'B', 'B', 'A', 'C', 'C', 'D', 'E', 'E', 'A', 'D' },
    { 'E', 'B', 'E', 'C', 'C', 'D', 'E', 'E', 'A', 'D' } };

    // Key to the questions
    char keys[] = { 'D', 'B', 'D', 'C', 'C', 'D', 'A', 'E', 'A', 'D' };

    //Loop for student
    for(int i = 0; i < 8; i++)
    {
        cout << "Enter Student #" << i + 1 << " Name: ";
        cin >> studentnames[i];
    }

    for(int i = 0; i < NUMBER_OF_STUDENTS; i++)
    {
        // Grade one student
        int correctCount = 0;
        for(int j = 0; j < NUMBER_OF_QUESTIONS; j++)
        {
            if(answers[i][j] == keys[j])
                correctCount++;
        }
        //output Student name and test Score 
        cout << "Student Name is : " << studentnames[i] << endl;
        cout << "Score of the test is " << correctCount << endl;
    }

    return 0;
}

Answer 1

您可以将score声明为double，或进行浮动计算并将得分乘以100

for(int i = 0; i < NUMBER_OF_STUDENTS; i++)
{
    // Grade one student
    int correctCount = 0;
    for(int j = 0; j < NUMBER_OF_QUESTIONS; j++)
    {
        if(answers[i][j] == keys[j])
            correctCount++;
    }
    score[i] = 100 * ((double)correctCount / (double)NUMBER_OF_QUESTIONS);

    cout 
        << "Name: " << studentnames[i] 
        << ", correctCount: " << correctCount 
        << ", average: " << score[i] << "\n";
}

与您的问题无关，但您也可以通过声明学生的姓名来使代码更容易调试，而不是每次都输入。您可以稍后注释掉用户输入部分。

//for(int i = 0; i < 8; i++)
//{
//  cout << "Enter Student #" << i + 1 << " Name: ";
//  cin >> studentnames[i];
//}
std::string studentnames[NUMBER_OF_STUDENTS] =
{ "n1","n2","n3","n4","n5","n6","n7","n8" };

单个和多个阵列

1 个答案: