Question

让我从这开始......我从来没有使用过.php脚本编程，而且编程方面还比较新，我正在开发一个以Android Studio IDE为中心的新项目，我通常用JAVA编写。我一直在尝试使用下面的.php脚本，我已根据需要进行修改。它工作得很好但是，我无法弄清楚如何进行多查询，基本上我希望得到我的回声＆＃39;但是如果有一个匹配到FSC / NIIN字段，那么它应该显示额外的匹配。

返回历史记录，为某些FSC / NIIN字段列出了多个部件号，我正在努力让它显示与库存号（FSC / NIIN）匹配的其他部件号。非常感谢任何帮助或建议！

<?php 
require "conn.php";
$FSC = $_POST["FSC"];
$NIIN = $_POST["NIIN"];
$mysql_qry = "select * from MYTAB where FSC like '$FSC' and NIIN like 
'$NIIN';";
$result = mysqli_query($conn ,$mysql_qry);

if(mysqli_num_rows($result) > 0) {
$row = mysqli_fetch_assoc($result);
$PART_NUMBER = $row["PART_NUMBER"];
$FSC = $row["FSC"];
$NIIN = $row["NIIN"];
$ITEM_NAME = $row["ITEM_NAME"];

echo $ITEM_NAME, ", " .$PART_NUMBER, ", " .$FSC, ", " .$NIIN;
} else {
echo "Query Failed! - No such NSN is loaded to the database! Please double 
check the information is correct and resubmit request...";
}

mysqli_close($con);

?>

Answer 1

您需要循环结果：

....
if(mysqli_num_rows($result) > 0) {
    while($row = mysqli_fetch_assoc($result)) { //<-----
        $PART_NUMBER = $row["PART_NUMBER"];
        $FSC = $row["FSC"];
        $NIIN = $row["NIIN"];
        $ITEM_NAME = $row["ITEM_NAME"];

        echo $ITEM_NAME, ", " .$PART_NUMBER, ", " .$FSC, ", " .$NIIN;
    }
} else {
...

你应该使用预备语句，看看如何在这里： How can I prevent SQL injection in PHP?

使用php建议MySql多查询

1 个答案: