如何从结果中创建一行

Question

我通过使用我的商店程序获得以下结果。在消除空值后，如何只获得一行结果。 ？

`cte_Sum
as
(
Select sum(NumberOfCode) as NumberOfCode, CodeName, Code, Quarters, Q1s, Q2s, Q3s, Q4s  
from cte_totals 
group by CodeName, Code, Quarters, Q1s, Q2s, Q3s, Q4s 
)
Select 
CodeName,Code, 
Case When Quarters = 'Q1' Then NumberOfCode End  as Q1_Number,
Case When Quarters = 'Q1' Then Q1s End  as Q1_Date, 
Case When Quarters = 'Q2' Then NumberOfCode End  as Q2_Number,
Case When Quarters = 'Q2' Then Q2s End  as Q2_Date,  
Case When Quarters = 'Q3' Then NumberOfCode End  as Q3_Number,
Case When Quarters = 'Q3' Then Q3s End  as Q3_Date, 
Case When Quarters = 'Q4' Then NumberOfCode End  as Q4_Number,
Case When Quarters = 'Q4' Then Q4s End  as Q4_Date
from cte_Sum`

预期结果。

Answer 1

使用聚合：

Select CodeName, Code, 
       sum(Case When Quarters = 'Q1' Then NumberOfCode End) as Q1_Number,
       max(Case When Quarters = 'Q1' Then Q1s End)  as Q1_Date, 
       sum(Case When Quarters = 'Q2' Then NumberOfCode End)  as Q2_Number,
       max(Case When Quarters = 'Q2' Then Q2s End)  as Q2_Date,  
       sum(Case When Quarters = 'Q3' Then NumberOfCode End)  as Q3_Number,
       max(Case When Quarters = 'Q3' Then Q3s End)  as Q3_Date, 
       sum(Case When Quarters = 'Q4' Then NumberOfCode End)  as Q4_Number,
       max(Case When Quarters = 'Q4' Then Q4s End)  as Q4_Date
from cte_Sum
group by CodeName, Code;

我不认为CTE会有所帮助。你也可以这样做：

Select CodeName, Code, 
       sum(Case When Quarters = 'Q1' Then NumberOfCode else 0 End) as Q1_Number,
       max(Case When Quarters = 'Q1' Then Q1s End)  as Q1_Date, 
       sum(Case When Quarters = 'Q2' Then NumberOfCode else 0 End)  as Q2_Number,
       max(Case When Quarters = 'Q2' Then Q2s End)  as Q2_Date,  
       sum(Case When Quarters = 'Q3' Then NumberOfCode else 0 End)  as Q3_Number,
       max(Case When Quarters = 'Q3' Then Q3s End)  as Q3_Date, 
       sum(Case When Quarters = 'Q4' Then NumberOfCode else 0 End)  as Q4_Number,
       max(Case When Quarters = 'Q4' Then Q4s End)  as Q4_Date
from cte_totals
group by CodeName, Code;

您也可以简化cte_totals，但您的问题并未显示该代码。

Answer 2

对于那些Q2-Q4列不为NULL的行，我会自行离开。

select t1.CodeName ,t1.Code , 
Q2.Q2_NUmber, Q2.Q2_DAte, 
Q3.Q3_NUmber, Q3.Q3_DAte, 
Q4.Q4_NUmber, Q4.Q4_DAte
from table t1
left join (select Code, Q2_Number, Q2_Date where Q2_Number is not NULL) Q2 on t1.Code = Q2.Code      
left join (select Code, Q3_Number, Q3_Date where Q3_Number is not NULL) Q3 on t1.Code = Q3.Code
left join (select Code, Q4_Number, Q4_Date where Q4_Number is not NULL) Q4 on t1.Code = Q4.Code