我在创建的数据库中创建新对象（特别是视图）时遇到问题。虽然此处报告了许多类似的问题，但请参阅permission denied for relation和permission denied for sequence，但是尽管研究了已接受的答案（在某些情况下，还有PostgreSQL文档），我还是无法解决这个问题。
以下是我正在运行的脚本片段，用于创建数据库，新角色，然后更改数据库的默认权限：
-- # Uncomment line below for debugging purposes
SET client_min_messages TO debug1;
CREATE DATABASE mydatabase WITH ENCODING 'UTF8' TEMPLATE template1;
-- Create user foo
CREATE ROLE foo LOGIN ENCRYPTED PASSWORD '29829932499gd' NOINHERIT;
\c mydatabase
--- this grants privileges on new objects generated in new database "mydatabase"
ALTER DEFAULT PRIVILEGES IN SCHEMA public GRANT ALL ON TABLES TO foo;
ALTER DEFAULT PRIVILEGES IN SCHEMA public GRANT SELECT ON ALL SEQUENCES IN SCHEMA public TO foo;
ALTER DEFAULT PRIVILEGES IN SCHEMA public GRANT ALL ON FUNCTIONS TO foo;
--- import DDL from SQL files (Ommitted for brevity sake)
当我尝试创建一个物化视图时，我意识到我试图从中选择的一个表（table_1）上存在权限错误。
我直接在CLI尝试了一个简单的查询：
mydatabase=> select * from table_1;
ERROR: permission denied for relation table_1
然后我在psql CLI（连接到 mydatabase 数据库）上手动输入了这个：
在SCHEMA public TO foo的所有表格中授予所有特权;
然后我得到了答复：
错误：关系表__2的权限被拒绝
以下是table_1和table_2的架构：
CREATE TABLE IF NOT EXISTS table_1 (
td DATE NOT NULL,
f1 REAL CHECK (f1 > 0) NOT NULL ,
f2 REAL CHECK (f2 > 0 and f2 >= f1 and f2 >= f3 and f2 >= f4) NOT NULL ,
f3 REAL CHECK (f3 > 0 and f3 <= f1 and f3 <= f2 and f3 <= f4) NOT NULL ,
f4 REAL CHECK (f4 > 0) NOT NULL,
f5 BIGINT CHECK (f5 > -1) DEFAULT 0 NOT NULL,
f6 BIGINT CHECK (f6 > -1) DEFAULT 0 NOT NULL,
moff SMALLINT DEFAULT 0 CHECK (moff > -1) NOT NULL,
flg_03_h BOOLEAN DEFAULT FALSE NOT NULL,
flg_03_l BOOLEAN DEFAULT FALSE NOT NULL,
flg_05_h BOOLEAN DEFAULT FALSE NOT NULL,
flg_05_l BOOLEAN DEFAULT FALSE NOT NULL,
flg_10_h BOOLEAN DEFAULT FALSE NOT NULL,
flg_10_l BOOLEAN DEFAULT FALSE NOT NULL,
flg_20_h BOOLEAN DEFAULT FALSE NOT NULL,
flg_20_l BOOLEAN DEFAULT FALSE NOT NULL,
flg_60_h BOOLEAN DEFAULT FALSE NOT NULL,
flg_60_l BOOLEAN DEFAULT FALSE NOT NULL,
flg_52w_h BOOLEAN DEFAULT FALSE NOT NULL,
flg_52w_l BOOLEAN DEFAULT FALSE NOT NULL,
flg_at_h BOOLEAN DEFAULT FALSE NOT NULL,
flg_at_l BOOLEAN DEFAULT FALSE NOT NULL,
flg_03v_h BOOLEAN DEFAULT FALSE NOT NULL,
flg_03v_l BOOLEAN DEFAULT FALSE NOT NULL,
flg_05v_h BOOLEAN DEFAULT FALSE NOT NULL,
flg_05v_l BOOLEAN DEFAULT FALSE NOT NULL,
flg_10v_h BOOLEAN DEFAULT FALSE NOT NULL,
flg_10v_l BOOLEAN DEFAULT FALSE NOT NULL,
flg_20v_h BOOLEAN DEFAULT FALSE NOT NULL,
flg_20v_l BOOLEAN DEFAULT FALSE NOT NULL,
flg_60v_h BOOLEAN DEFAULT FALSE NOT NULL,
flg_60v_l BOOLEAN DEFAULT FALSE NOT NULL,
flg_52wv_h BOOLEAN DEFAULT FALSE NOT NULL,
flg_52wv_l BOOLEAN DEFAULT FALSE NOT NULL,
flg_atv_h BOOLEAN DEFAULT FALSE NOT NULL,
flg_atv_l BOOLEAN DEFAULT FALSE NOT NULL,
ar_1w REAL DEFAULT -99999 NOT NULL,
ar_2w REAL DEFAULT -99999 NOT NULL,
ar_1m REAL DEFAULT -99999 NOT NULL,
ar_3m REAL DEFAULT -99999 NOT NULL,
ar_1w_mzs REAL DEFAULT -99999 NOT NULL,
ar_2w_mzs REAL DEFAULT -99999 NOT NULL,
ar_1m_mzs REAL DEFAULT -99999 NOT NULL,
ar_3m_mzs REAL DEFAULT -99999 NOT NULL,
PRIMARY KEY (td, moff)
);
CREATE INDEX idx_tb1_flg03f2 ON table_1 (td, flg_03_h);
CREATE INDEX idx_tb1_flg03f3 ON table_1 (td, flg_03_l);
CREATE INDEX idx_tb1_flg05f2 ON table_1 (td, flg_05_h);
CREATE INDEX idx_tb1_flg05f3 ON table_1 (td, flg_05_l);
CREATE INDEX idx_tb1_flg10f2 ON table_1 (td, flg_10_h);
CREATE INDEX idx_tb1_flg10f3 ON table_1 (td, flg_10_l);
CREATE INDEX idx_tb1_flg20f2 ON table_1 (td, flg_20_h);
CREATE INDEX idx_tb1_flg20f3 ON table_1 (td, flg_20_l);
CREATE INDEX idx_tb1_flg60f2 ON table_1 (td, flg_60_h);
CREATE INDEX idx_tb1_flg60f3 ON table_1 (td, flg_60_l);
CREATE INDEX idx_tb1_flg52wf2 ON table_1 (td, flg_52w_h);
CREATE INDEX idx_tb1_flg52wf3 ON table_1 (td, flg_52w_l);
CREATE INDEX idx_tb1_flgatf2 ON table_1 (td, flg_at_h);
CREATE INDEX idx_tb1_flgatf3 ON table_1 (td, flg_at_l);
CREATE INDEX idx_tb1_flg03f5f2 ON table_1 (td, flg_03v_h);
CREATE INDEX idx_tb1_flg03f5f3 ON table_1 (td, flg_03v_l);
CREATE INDEX idx_tb1_flg05f5f2 ON table_1 (td, flg_05v_h);
CREATE INDEX idx_tb1_flg05f5f3 ON table_1 (td, flg_05v_l);
CREATE INDEX idx_tb1_flg10f5f2 ON table_1 (td, flg_10v_h);
CREATE INDEX idx_tb1_flg10f5f3 ON table_1 (td, flg_10v_l);
CREATE INDEX idx_tb1_flg20f5f2 ON table_1 (td, flg_20v_h);
CREATE INDEX idx_tb1_flg20f5f3 ON table_1 (td, flg_20v_l);
CREATE INDEX idx_tb1_flg60f5f2 ON table_1 (td, flg_60v_h);
CREATE INDEX idx_tb1_flg60f5f3 ON table_1 (td, flg_60v_l);
CREATE INDEX idx_tb1_flg52f5wf2 ON table_1 (td, flg_52wv_h);
CREATE INDEX idx_tb1_flg52f5wf3 ON table_1 (td, flg_52wv_l);
CREATE INDEX idx_tb1_flgatf5f2 ON table_1 (td, flg_atv_h);
CREATE INDEX idx_tb1_flgatf5f3 ON table_1 (td, flg_atv_l);
CREATE INDEX idx_tb1_ar_1w ON table_1 (td, ar_1w);
CREATE INDEX idx_tb1_ar_2w ON table_1 (td, ar_2w);
CREATE INDEX idx_tb1_ar_1m ON table_1 (td, ar_1m);
CREATE INDEX idx_tb1_ar_3m ON table_1 (td, ar_3m);
CREATE INDEX idx_tb1_ar_1w_mz ON table_1 (td, ar_1w_mzs);
CREATE INDEX idx_tb1_ar_2w_mz ON table_1 (td, ar_2w_mzs);
CREATE INDEX idx_tb1_ar_1m_mz ON table_1 (td, ar_1m_mzs);
CREATE INDEX idx_tb1_ar_3m_mz ON table_1 (td, ar_3m_mzs);
CREATE TABLE IF NOT EXISTS table_2 (
id SERIAL PRIMARY KEY NOT NULL,
name TEXT NOT NULL
);
CREATE UNIQUE INDEX idxu_table2_nm ON table_2 (name);
可以看出， table_1 和 table_2 之间存在 NO 关系，所以我怀疑postgreSQL给出的错误消息实际上是红鲱鱼（即误导）。
最后一件事。我使用 Docker * 来部署我的postgreSQL服务 - 所以上面的脚本由docker运行。我运行docker run时创建了数据库 - 但是，当我以用户foo登录时，我尝试创建新视图（甚至在任何表上运行简单的SELECT），我得到错误：
错误：关系$ table_name
的权限被拒绝
我注意到的另一件奇怪的事情（当我在psql命令中运行\z时）显示数据库中没有任何表具有任何权限：
Access privileges
Schema | Name | Type | Access privileges | Column privileges | Policies
--------+-----------------------------------------------------------+----------+-------------------+-------------------+----------
public | mdb_company_financials_balsheet | table | | |
public | mdb_company_financials_cashflow | table | | |
public | mdb_company_financials_income_stmt | table | | |
public | mdb_ccy_group_member | table | | |
那么，是什么导致了这个权限问题，我该如何解决呢？
*（不确定是否是相关信息）。
[[附录]
version
------------------------------------------------------------------------------------------
PostgreSQL 9.6.5 on x86_64-pc-linux-gnu, compiled by gcc (Debian 4.9.2-10) 4.9.2, 64-bit
答案 0 :(得分：1)
经过一些研究，这对我有用。 psql（9.6.12）
-- login to postgres database server as postgres user.
ssh <user>>@hostname.<domain>>.com
sudo su postgres
id
psql
postgres=# create user sentry_read with login password 'sentry_read';
postgres=# du+
postgres=# \l+
-- **very important: make sure we should connect required database before we grant to user.**
postgres=# \c sentry
postgres=# \dt
sentry=# \dp SENTRY_VERSION
sentry=# select * from "SENTRY_VERSION";
sentry=# GRANT SELECT ON ALL TABLES IN SCHEMA public TO sentry_read;
postgres=# \q
[user@hostname ~]$ psql -U sentry_read -d sentry -h hostname.<domain>>.com -W
sentry=> select * from "SENTRY_VERSION";