Question

ID  can eat
1   apples
1   pears
2   grapes
2   pears
3   apples
3   oranges
3   pears
4   oranges
5   apples
6   pears
6   oranges

使用上表作为数据示例。如何找到所有不能吃苹果的人的身份证？

Answer 1

按id分组，只收集那些没有apples条目的群组

select id
from your_table
group by id
having sum(case when can_eat = 'apples' then 1 else 0 end) = 0

Answer 2

只需选择id except可以吃苹果的人：

select id from tablename
except
select id from tablename where caneat = 'apples'

Answer 3

SELECT Sheet1.ID
FROM Sheet1 LEFT JOIN (SELECT Sheet1.ID
FROM Sheet1
WHERE (((Sheet1.caneat)="apples"))
GROUP BY Sheet1.ID)  AS CanEatApplesList ON Sheet1.ID = CanEatApplesList.ID
WHERE (((CanEatApplesList.ID) Is Null))
GROUP BY Sheet1.ID;

Answer 4

这是最简单的可能解决方案之一：

SELECT DISTINCT a.ID
FROM TableName a
WHERE can_eat NOT in ('apples') 
AND a.ID NOT in (SELECT distinct b.ID
FROM TableName b WHERE b.can_eat = 'apples');

SQL在同一个表中发现缺少针对多个ID的特定字符串

4 个答案: