正则表达式以匹配给定的要求

Question

我有一个字符串：

s = '((FILTER( "SalesVelocity"."OrderHeader"."#Opportunities" 
 USING "SalesVelocity"."Opportunity_1"."OpportunityStatusCategory"=''OPEN''))*
 (FILTER("SalesVelocity"."OrderHeader"."OpportunityRevenue" 
 USING "SalesVelocity"."Opportunity_1"."OpportunityStatusCategory"=''OPEN'')/
 FILTER("SalesVelocity"."OrderHeader"."#Opportunities" 
 USING "SalesVelocity"."Opportunity_1"."OpportunityStatusCategory"=''OPEN''))*
 (FILTER ( "SalesVelocity"."OrderHeader"."#Opportunities" 
 USING "SalesVelocity"."Opportunity_1"."OpportunityStatusCategory" = ''WON'') / 
 "SalesVelocity"."OrderHeader"."#Opportunities" ))/
 ((1.0 * "SalesVelocity"."OrderHeader"."TotalSalesCycleOppty")  / 
 FILTER("SalesVelocity"."OrderHeader"."#Opportunities" 
 USING "SalesVelocity"."Opportunity_1"."OpportunityStatusCategory" = ''WON''))'

它将表格引用为"SchemaName"."TableName"."ColumnName" 我需要使用Schema提取所有表的信息 "SalesVelocity"."OrderHeader" "SalesVelocity"."Opportunity_1"

import re
pat = r'".*?\"\.".*?\"'             #See Note at the bottom of the answer
s = '((FILTER( "SalesVelocity"."OrderHeader"."#Opportunities" 
 USING "SalesVelocity"."Opportunity_1"."OpportunityStatusCategory"=''OPEN''))*
 (FILTER("SalesVelocity"."OrderHeader"."OpportunityRevenue" 
 USING "SalesVelocity"."Opportunity_1"."OpportunityStatusCategory"=''OPEN'')/
 FILTER("SalesVelocity"."OrderHeader"."#Opportunities" 
 USING "SalesVelocity"."Opportunity_1"."OpportunityStatusCategory"=''OPEN''))*
 (FILTER ( "SalesVelocity"."OrderHeader"."#Opportunities" 
 USING "SalesVelocity"."Opportunity_1"."OpportunityStatusCategory" = ''WON'') / 
 "SalesVelocity"."OrderHeader"."#Opportunities" ))/
 ((1.0 * "SalesVelocity"."OrderHeader"."TotalSalesCycleOppty")  / 
 FILTER("SalesVelocity"."OrderHeader"."#Opportunities" 
 USING "SalesVelocity"."Opportunity_1"."OpportunityStatusCategory" = ''WON''))'
match1 = re.findall(pat, s)
print(match1)

它输出为：

['"SalesVelocity"."OrderHeader"', 
'"#Opportunities" USING "SalesVelocity"."Opportunity_1"', 
'"OpportunityStatusCategory"=OPEN))*(FILTER("SalesVelocity"."OrderHeader"', 
'"OpportunityRevenue" USING "SalesVelocity"."Opportunity_1"', 
'"OpportunityStatusCategory"=OPEN)/FILTER("SalesVelocity"."OrderHeader"', 
'"#Opportunities" USING "SalesVelocity"."Opportunity_1"', 
'"OpportunityStatusCategory"=OPEN))*(FILTER ("SalesVelocity"."OrderHeader"', 
'"#Opportunities" USING "SalesVelocity"."Opportunity_1"', 
'"OpportunityStatusCategory" = WON) / "SalesVelocity"."OrderHeader"', 
'"#Opportunities" ))/((1.0 * "SalesVelocity"."OrderHeader"', 
'"TotalSalesCycleOppty")  / FILTER("SalesVelocity"."OrderHeader"', 
'"#Opportunities" USING "SalesVelocity"."Opportunity_1"']

哪个不正确，例如第二个值：

('"#Opportunities" USING "SalesVelocity"."Opportunity_1"')

我的表情检查是从“然后。？开始，所有字符到达\”然后再点“然后。？”所有字符，直到达到\“

我错过了什么？

Answer 1

以下正则表达式（根据Wiktor Stribizew的建议进行修改应该有效）："[^"]*?\"\."[^"]*\"

Answer 2

这就是你需要的吗？

import re

s = '''((FILTER( "SalesVelocity"."OrderHeader"."#Opportunities" USING "SalesVelocity"."Opportunity_1"."OpportunityStatusCategory"='OPEN'))*(FILTER("SalesVelocity"."OrderHeader"."OpportunityRevenue" USING "SalesVelocity"."Opportunity_1"."OpportunityStatusCategory"='OPEN')/FILTER("SalesVelocity"."OrderHeader"."#Opportunities" USING "SalesVelocity"."Opportunity_1"."OpportunityStatusCategory"='OPEN'))*(FILTER ( "SalesVelocity"."OrderHeader"."#Opportunities" USING "SalesVelocity"."Opportunity_1"."OpportunityStatusCategory" = 'WON') / "SalesVelocity"."OrderHeader"."#Opportunities" ))/((1.0 * "SalesVelocity"."OrderHeader"."TotalSalesCycleOppty")  / FILTER("SalesVelocity"."OrderHeader"."#Opportunities" USING "SalesVelocity"."Opportunity_1"."OpportunityStatusCategory" = 'WON'))'''

pat = r'"[^"]*?"\."[^"]*?"'             #See Note at the bottom of the answer

match1 = re.findall(pat, s)
print(match1)

输出：

['"SalesVelocity"."OrderHeader"', '"SalesVelocity"."Opportunity_1"', '"SalesVelocity"."OrderHeader"', '"SalesVelocity"."Opportunity_1"', '"SalesVelocity"."OrderHeader"', '"SalesVelocity"."Opportunity_1"', '"SalesVelocity"."OrderHeader"', '"SalesVelocity"."Opportunity_1"', '"SalesVelocity"."OrderHeader"', '"SalesVelocity"."OrderHeader"', '"SalesVelocity"."OrderHeader"', '"SalesVelocity"."Opportunity_1"']

Answer 3

了解回溯

• ".*?"匹配下一个"和"
之后的最短子序列
• ".*?"\.匹配下一个"和".
之后的最短子序列

因此".*?"\.与"#Opportunities" USING "SalesVelocity".匹配，因为在"\.匹配失败后，它会回溯到.*

否定前瞻更具表现力，因为它准确指定了不需要的令牌，

"(?:(?!").)*"\.".*?"

另一个修复方法是使用“。*？”

周围的原子组

"(?>.*?")\.".*?"

但在你的情况下，使用否定字符更有效：[^"]*，因为它避免了回溯。