Question

我想在删除用户后显示消息，但我不知道该怎么做。我尝试创建req.session属性然后使用它们但它们在GET路由中不可用。你知道如何修复这段代码吗？

＆＃13;

router.get("/", mid.isExpired, mid.isLoggedIn, mid.isAdmin, (req, res) => {
  let currentMessage = req.session.message;
  let currentState = req.session.state;
  req.session.message = undefined;
  req.session.state = undefined;
  console.log(currentState, currentMessage); //undefined
  user.getAll()
    .then(result => {
      res.render("users", {
        name: req.user,
        users: result,
        msg: currentMessage,
        state: currentState
      })
    })
});


// delete route

router.delete("/delete/:id", mid.isExpired, mid.isLoggedIn, mid.isAdmin, (req, res) => {
  user.del(req.params.id)
    .then(() => {
      req.session.message = "Some message!"
      req.session.state = true;
    })
});

// jquery 

function ajaxDelete(ev, url) {
  ev.preventDefault();
  $.ajax({
    url: url,
    type: "DELETE"
  });
}

delBtn.click(function(e) {
  var user = $(this).data("user");
  ajaxDelete(e, "/users/delete/" + user);
  window.location.href = "/users";
})

＆＃13;

Answer 1

使用res参数，并创建一个名为message

的变量

HttpHeaders

然后

const message= 'MyMessage';

输出

res.json ({message}) // es6 feature

Answer 2

在您的场景中，据我所知，您希望发送JSON作为响应。您可以使用此代码

router.delete("/delete/:id", mid.isExpired, mid.isLoggedIn, mid.isAdmin, (req, res) => {
  user.del(req.params.id)
    .then(() => {
      var response = { message : "Some message!",
                       state   : true };
      return res.json(response);
    })
});

关键字＆＃39;返回＆＃39;根据您的要求

Answer 3

路由器和会话是任何nodeJs App的中间件，如果路由器在会话之前添加如下：

app.use(router)
app.use(session(...));

然后会话中间件不会被路由器处理的任何请求调用。因此改变添加路由器和会话中间件的顺序，如此

app.use(session(...));
app.use(router)

如何在DELETE路由中发送消息 - express.js

3 个答案: