Question

我的表格如下：

id       time_stamp                 evenid    
1001    2017-09-05 09:35:00         1(in)
1002    2017-09-05 11:00:00         0(out)

我使用下面的查询，但得到的却不是确切的答案。错误第二天在所需的日期

;WITH InOut (empId, EntryTime, ExitTime,POINTID,EVENTID,Belongs_to) as
(SELECT  emp_reader_id ,
        a1.DT ,
        ( SELECT    MIN(a2.DT)
          FROM      trnevents a2
          WHERE     a1.emp_reader_id = a2.emp_reader_id
                    AND a1.DT < a2.DT
        ),a1.DeviceSerialNumber,EVENTID,Belongs_to
FROM    trnevents a1    

)
SELECT empId ,
       EntryTime ,
       ExitTime,EVENTID, Belongs_to
         ,CONVERT( CHAR(11), '2017/12/30', 103 ) as StartDate
      ,CONVERT( CHAR(11), '2018/01/15', 103 ) as ToDate
       ,case when convert(time,dateadd(ms,DATEDIFF(SECOND, EntryTime, ExitTime)*1000,0),114) is not null
        then convert(time,dateadd(ms,DATEDIFF(SECOND, EntryTime, ExitTime)*1000,0),114) else '00:00' end as Worked FROM InOut  A

输出错误：第二天也是

   EMP_NO       INTIME                OUTTIME             DT          WORKED
    101 2018-01-08 09:11:14.000 2018-01-08 12:07:22.000 2018-01-08      02:56:08.0000000
    101 2018-01-08 12:07:22.000 2018-01-08 14:35:33.000 2018-01-08      02:28:11.0000000
    101 2018-01-08 14:35:33.000 **2018-01-09 09:14:00.000** 2018-01-08  18:38:27.0000000
    101 2018-01-09 09:14:00.000 2018-01-09 14:28:23.000 2018-01-09      05:14:23.0000000

我想要的输出：

SL# Emp# Employee Name           IN                    OUT           Worked 
2   107    Nisham M    24/Sep/2017 8:34:00AM 24/Sep/2017 10:15:00AM 01:41:00
                      24/Sep/2017 10:19:00AM 24/Sep/2017 12:20:00PM 02:01:00
                      24/Sep/2017 12:25:00PM 24/Sep/2017 12:54:00PM 00:29:00
                        24/Sep/2017 2:13:00PM 24/Sep/2017 2:14:00PM 00:01:00
                        24/Sep/2017 2:19:00PM 24/Sep/2017 5:25:00PM 03:06:00
                        10/Oct/2017 2:00:00PM 10/Oct/2017 2:52:00PM 00:52:00
                        10/Oct/2017 3:15:00PM     NULL                -
                       11/Oct/2017 8:26:00AM 11/Oct/2017 10:29:00AM 02:03:00
                        19/Oct/2017 1:59:00PM 19/Oct/2017 5:56:00PM 03:57:00
Total Shift Hours Total Basic Hours OT Normal Hours Total Hours Worked
    210             159:20:00         00:00:00          159:20:00

我坚持到这里搜索大多数但没有获得所需的输出任何人的帮助

Answer 1

根据to this answer，添加：

AND DATEDIFF(DAY, a1.DT, a2.DT) = 0

对于WHERE条款，应确保开始日期和结束日期在同一天，但如果有人在午夜过夜会怎样？你的帖子也暗示你也把结束时间作为开始时间，所以你可以这样做：

AND a1.EVENTID = 1 AND a2.EVENTID = 0

如果两者都不合适，请进一步描述您的问题并提供更多样本数据。

全力以赴，冲出一名员工？

1 个答案: