我能够编写一个打印出两个数组交集的函数。但是,我试图获得交叉点成员的价值。
如果我们的最终交叉点为{6, 12}
,我应该返回2作为值,因为我有2个成员。我的回报值是1,我不知道自己做错了什么。
int main()
{
int data1[] = { 3, 6, 9, 12};
int data2[] = { 2, 4, 6, 8, 10, 12 };
int result[] = {};
size_t length1 = sizeof(data1)/sizeof(int);
size_t length2 = sizeof(data2)/sizeof(int);
size_t resultMax= 0;
int i =0;
int j =0;
while (i < length1 && j < length2)
{
if (data1[i] < data2[j])
{
i++;
}
else if (data2[j] < data1[i])
{
j++;
}
else if (data1[i] == data2[j])
{
result[i] = data1[i];
cout << "valor : " << result[i] << endl; // output is 6 and 12
i++;
j++;
resultMax = sizeof(result[i])/sizeof(int);
}
}
cout << "Final Size: "<< resultMax; //output is 0
return resultMax;
}
答案 0 :(得分:1)
使用std::vector代替数组。
# include<iostream>
# include<vector>
using namespace std;
int main()
{
vector<int> data1 = { 3, 6, 9, 12}, data2 = { 2, 4, 6, 8, 10, 12 }, result;
int i = 0, j = 0, length1 = data1.size(), length2 = data2.size();
while (i < length1 && j < length2)
{
if (data1[i] < data2[j])
i++;
else if (data2[j] < data1[i])
j++;
else if (data1[i] == data2[j])
{
result.push_back(data1[i]);
cout << "valor : " << data1[i] << endl;
i++;
j++;
}
}
cout << "Final Size: "<< result.size();
return 0;
}
答案 1 :(得分:1)
使用算法库,特别是std::set_intersection。
以下是上面链接的cppreference页面稍微改编的示例:
int main()
{
std::vector<int> v1{3, 6, 9, 12};
std::vector<int> v2{2, 4, 6, 8, 10, 12 };
std::sort(v1.begin(), v1.end());
std::sort(v2.begin(), v2.end());
std::vector<int> v_intersection;
std::set_intersection(v1.begin(), v1.end(),
v2.begin(), v2.end(),
std::back_inserter(v_intersection));
std::cout << "Final Size: "<< v_intersection.size();
}