Question

-UIApplication.shared.openURL(url)
-UIApplicartion.shared.open(url,options: [:],completionHandler: nil)

我可以在iOS9和iOS10中使用这两个选项吗？

iOS9和/或iOS10是否支持UIApplication.shared.openURL(url)？

Answer 1

你可以试试这个

guard let url = URL(string: "http://www.google.com") else {
  return //be safe
}

if #available(iOS 10.0, *) {
    UIApplication.shared.open(url, options: [:], completionHandler: nil)
} else {
    UIApplication.shared.openURL(url)
}

Answer 2

是的，你必须把它们放在这样的条件下才能使用它们，

func open(scheme: String) {
  if let url = URL(string: scheme) {
    if #available(iOS 10, *) { // For ios 10 and greater
      UIApplication.shared.open(url, options: [:],
        completionHandler: {
          (success) in
           print("Open \(scheme): \(success)")
       })
    } else { // for below ios 10.
      let success = UIApplication.shared.openURL(url)
      print("Open \(scheme): \(success)")
    }
  }
}

Answer 3

guard let url = URL(string: "https://www.google.com/") else { return }
        if #available(iOS 10.0, *) {
            UIApplication.shared.open(url)
        } else {
            // Fallback on earlier versions
            let svc = SFSafariViewController(url: url)
            present(svc, animated: true, completion: nil)
        }

当我想在iOS 9及更高版本的Safari浏览器中打开URL时，使用了此选项。

openURL并在IOS 9/10中开放

3 个答案: