从设备到设备的Android Firebase云消息传递

时间:2018-01-23 01:48:53

标签: java android firebase-cloud-messaging

我正在尝试将firebase设备发送到设备推送通知,因此我的代码如下所示。

private void sendNotification(final String token) {

    new AsyncTask<Void,Void,Void>(){

        @Override
        protected Void doInBackground(Void... voids) {
            try {
                OkHttpClient client=new OkHttpClient();
                JSONObject json=new JSONObject();
                JSONObject dataJson=new JSONObject();
                dataJson.put("body","Hello, I am body");
                dataJson.put("title","I am title");
                json.put("notification",dataJson);
                json.put("to",token);
                RequestBody body=RequestBody.create(JSON,json.toString());
                Request request=new Request.Builder()
                        .header("Authorization","key="+LEGACY_SERVER_KEY)
                        .url("https://fcm.googleapis.com/fcm/send")
                        .post(body)
                        .build();
                Response response=client.newCall(request).execute();
                String finalResponse=response.body().string();

                //Toast.makeText(MainActivity.this, finalResponse, Toast.LENGTH_SHORT).show();
            }catch (Exception e){
                Toast.makeText(MainActivity.this, "Exception occured", Toast.LENGTH_SHORT).show();
            }
            return null;
        }
    }.execute();
}

此处的问题是通知未发送到其他设备。但是,当我取消注释Toast(try块的最后一行)时,通知将成功发送并立即显示应用程序停止工作。有人请帮忙。

当我取消注释Toast(try块的最后一行)时,会发送通知,但不幸的是app停止了。 logcat是:

01-23 07:17:11.907 4694-4731/bhavana.apps.saveme E/AndroidRuntime: FATAL EXCEPTION: AsyncTask #1
    Process: bhavana.apps.saveme, PID: 4694
    java.lang.RuntimeException: An error occurred while executing doInBackground()
        at android.os.AsyncTask$3.done(AsyncTask.java:353)
        at java.util.concurrent.FutureTask.finishCompletion(FutureTask.java:383)
        at java.util.concurrent.FutureTask.setException(FutureTask.java:252)
        at java.util.concurrent.FutureTask.run(FutureTask.java:271)
        at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:245)
        at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1162)
        at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:636)
        at java.lang.Thread.run(Thread.java:764)
     Caused by: java.lang.RuntimeException: Can't toast on a thread that has not called Looper.prepare()
        at android.widget.Toast$TN.<init>(Toast.java:390)
        at android.widget.Toast.<init>(Toast.java:114)
        at android.widget.Toast.makeText(Toast.java:277)
        at android.widget.Toast.makeText(Toast.java:267)
        at bhavana.apps.saveme.MainActivity$6.doInBackground(MainActivity.java:199)
        at bhavana.apps.saveme.MainActivity$6.doInBackground(MainActivity.java:176)
        at android.os.AsyncTask$2.call(AsyncTask.java:333)
        at java.util.concurrent.FutureTask.run(FutureTask.java:266)
        at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:245) 
        at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1162) 
        at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:636) 
        at java.lang.Thread.run(Thread.java:764) 

3 个答案:

答案 0 :(得分:0)

您只能在UI线程中显示Toasts 删除此行或将其移至onPostExecute

Toast.makeText(MainActivity.this, "Exception occured", Toast.LENGTH_SHORT).show();

答案 1 :(得分:0)

Toast.makeText()需要在UI线程中执行。尝试将其替换为:

new Handler(Looper.getMainLooper()).post(new Runnable() {
    @Override
    public void run() {
        Toast.makeText(MainActivity.this, "Exception occured", Toast.LENGTH_SHORT).show();
    }
});

如果您只需要调试,只需使用Log:

android.util.Log.i("debug", "success msg: " + finalResponse);

您可以通过覆盖doInBackground()

来检查onPostExecute()的状态
@Override
protected void onPostExecute(Boolean result) {
    android.util.Log.i("debug", "onPostExecute: " + result);
}

这假设onPostExecute()返回Boolean,所以:

@Override
protected Boolean doInBackground(Void... params) {
    ......

    // return true on success
    if (success) {
        return true;
    }

    return false;
}

类需要以这种方式定义:

new AsyncTask<Void, Void, Boolean>(){

答案 2 :(得分:0)

  

引起:java.lang.RuntimeException:无法在一个线程上进行吐司   没有调用Looper.prepare()

您应该使用runOnUiThread

  

在UI线程上运行指定的操作。如果当前线程是   UI线程,然后立即执行操作。如果是当前的   线程不是UI线程,操作被发布到事件队列   UI线程。

runOnUiThread(new Runnable() {
      public void run() {
         Toast.makeText(MainActivity.this, "Exception occured", Toast.LENGTH_SHORT).show();
      }
 });