Question

我想为我的解析器编写单元测试，需要在其构造函数中使用ActivatedRouteSnapshot，如下所示：

export class MyResolver {
  constructor () {
    // ...
  }

  resolve (private route: ActivatedRouteSnapshot) {
    callFoo(route.params.val);
  }
};

但是在我的单元测试中，用模拟数据提供激活路由快照的最佳方法是什么？当我尝试使用我需要的属性创建一个对象时，我收到一个错误，它无法转换为ActivatedRouteSnapshot：

it('should call foo', inject([MyResolver], async (myResolver: MyResolver) => {
  const mockRoute = {
    params: {
      val: '1234'
    };
  };

  sinon.spy(callFoo);
  myResolver.resolve(mockRoute); // This is the line that errors
  expect(callFoo.calledWith('1234')).to.be.true;
}));

错误：

Type '{ params: { val: string; }; }' cannot be converted to type 'ActivatedRouteSnapshot'.

如何提供模拟的ActivatedRouteSnapshot以传递给我的解析器？

Answer 1

我不确定这是否是最漂亮的解决方案，但您可以像这样嘲笑这条路线：

let route = createSpyObj('Route', ['']);
route.params = {
  val: '1234'
}

Answer 2

您必须提供这样的活动路线：

import {TestBed} from '@angular/core/testing';
import {SomeResolver} from './some.resolver';
import {ActivatedRoute, convertToParamMap} from '@angular/router';
import {of} from 'rxjs';

describe('SomeResolver', () => {
  let someResolver: SomeResolver;
  let route: ActivatedRoute;

  TestBed.configureTestingModule({
    providers: [
      {
        provide: ActivatedRoute,
        useValue: {snapshot: {paramMap: convertToParamMap({id: 'one-id'})}}
      },
      SomeResolver
    ]
  });

  beforeEach(() => {
    heroResolver = TestBed.get(HeroResolver);
    route = TestBed.get(ActivatedRoute);
  });

  it('should resolve', (() => {
    someResolver.resolve(route.snapshot);
  }));
});

查看更复杂的示例here。

Answer 3

如果目的只是将模拟传递给解析器，则不必使用createSpyObj，如其他答案中所建议。另外，最好在解决方案中添加类型安全性：

const mock = <T, P extends keyof T>(obj: Pick<T, P>): T => obj as T;

it('should call foo', () => {
    const route = mock<ActivatedRouteSnapshot, 'params'>({
        params: {
            val: '1234'
        }
    });

    const resolver = createTheResolver();
    const resolverParams = resolver.resolve(route);
    ...
});

Answer 4

就我而言，这是最简单的事情（这也允许我写入通常为只读的“父”属性：

const route = Object.assign({}, ActivatedRouteSnapshot.prototype, {
  params: {
    myParam: 'some_value'
  },
  parent: {
    params: {
      myParentParam: 'some_other_value'
    }
  }
});

然后你只需像这样用“路由”调用你的解析器：

it('should do something with my activated route params', (done) => {
const route = Object.assign({}, ActivatedRouteSnapshot.prototype, {
  params: {
    myParam: 'some_value'
  },
  parent: {
    params: {
      myParentParam: 'some_other_value'
    }
  }
});
service.resolve(route).subscribe(res => {
  expect( ... )
  done();
});
});

Answer 5

请注意，如果您愿意，您也可以简单地将对象转换为 ActivatedRouteSnapshot：

const mockRoute = {paramMap: convertToParamMap({'id': '123'})} as 
    ActivatedRouteSnapshot;

resolver.resolve(mockRoute);

单元测试解析器时如何模拟ActivatedRouteSnapshot

5 个答案: