Question

我正在编写一个打印2个方框的程序，如下图所示：

我尝试了下面的程序，但没有给出预期的输出。

#include<iostream>

using namespace std;

int main()
{
    // Considering each box as a separate one
    for(int i = 1; i <= 2; i++)
    {           
    cout << "+---+ " << endl;
    cout << "|  " << i << "| " << endl;
    cout << "|   | " << endl;
    cout << "|   | " << endl;
    cout << "+---+ ";
    }

    return 0;
}

我得到的输出：

+---+ 
|  1| 
|   | 
|   | 
+---+ +---+ 
|  2| 
|   | 
|   | 
+---+

请在我错过的地方帮助我。任何帮助或暗示都将受到高度赞赏。

Answer 1

您不能将每个框视为一个单独的框，因为您将它们作为字符打印到终端中，这是逐行完成的。您必须首先打印所有框的顶部，然后打印所有框的下一行等。

如果要打印可变数量的盒子，这将是解决方案：

int main() {
    using namespace std;
    unsigned numberOfBoxes = 10;

    for (unsigned i = 0; i < numberOfBoxes; ++i)
        cout << "+---+" << (i == numberOfBoxes - 1 ? "\n" : " ");
    for (unsigned i = 0; i < numberOfBoxes; ++i)
        cout << "|  " << i << "|" << (i == numberOfBoxes - 1 ? "\n" : " ");
    for (unsigned i = 0; i < numberOfBoxes; ++i)
        cout << "|   |" << (i == numberOfBoxes - 1 ? "\n" : " ");
    for (unsigned i = 0; i < numberOfBoxes; ++i)
        cout << "|   |" << (i == numberOfBoxes - 1 ? "\n" : " ");
    for (unsigned i = 0; i < numberOfBoxes; ++i)
        cout << "+---+ ";
}

如果循环在最后一次迭代中或者添加空格，(i == numberOfBoxes - 1 ? "\n" : " ")就是要添加新行。

Answer 2

如果您在逻辑上跟踪for循环，您将看到如何一次打印一个盒子，堆叠在另一个盒子的顶部。

您需要确保在同一行上打印所有框的顶部，然后移动到所有框的主体，依此类推，直到所有框都已打印并且＃34;并行＆＃34 ;

为此，您可以在自己的for循环中打印每一行。例如：

#include<iostream>

using namespace std;

int main()
{
    for(int i = 1; i <= 2; i++) cout << "+---+ ";
    cout << endl;
    for(int i = 1; i <= 2; i++) cout << "|  " << i << "| ";
    cout << endl;
    for(int i = 1; i <= 2; i++) cout << "|   | ";
    cout << endl;
    for(int i = 1; i <= 2; i++) cout << "|   | ";
    cout << endl;
    for(int i = 1; i <= 2; i++) cout << "+---+ ";

    return 0;
}

Answer 3

Maros答案的延伸：

如果您想要以表格或矩阵的形式打印多行和多列：

int main() {
    using namespace std;
    unsigned numberOfColumns = 2, numberOfRows = 2;

    for (unsigned int i = 1; i <= numberOfRows; ++i) {
        for (unsigned j = 1; j <= numberOfColumns; ++j)
            cout << "+---+" << (j == numberOfColumns ? "\n" : " ");
        for (unsigned j = 1; j <= numberOfColumns; ++j)
            cout << "|  " << j + (numberOfColumns *(i-1)) << "|" << (j == numberOfColumns ? "\n" : " ");
        for (unsigned j = 1; j <= numberOfColumns; ++j)
            cout << "|   |" << (j == numberOfColumns ? "\n" : " ");
        for (unsigned j = 1; j <= numberOfColumns; ++j)
            cout << "|   |" << (j == numberOfColumns ? "\n" : " ");
        for (unsigned j = 1; j <= numberOfColumns; ++j)
            cout << "+---+ ";
        cout << endl;
    }   
    return 0;
}

如果此矩阵超出值9，则必须添加条件。

用C ++打印盒子图案

3 个答案: