Question

我想从我的[object object] 删除所有json而不是基于密钥，但是基于值i，e（[object object]）。

这是我的json

var allProductSpecification = {
            "Vinyl_Backlite": [{
              "Price": "280",
              "Quantity": "1",
              "Amount": "280"
            }],
            "Steel": [{
              "Price": "18",
              "Quantity": "1",
              "Amount": "18"
            }],
            "0": "[object Object]",
            "1": "[object Object]"
          }
   
   allProductSpecification = JSON.parse(allProductSpecification);
   
   delete  allProductSpecification[0];
   
    delete  allProductSpecification[1];
   
   console.log(allProductSpecification);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

这是我如何从键中删除[object object]：0

delete  allProductSpecification[0];

问题：如何动态[object object]动态

Answer 1

您可以使用条件array#reduce仅添加值不为[object Object]的键。

＆＃13;

var allProductSpecification = { "Vinyl_Backlite": [{ "Price": "280", "Quantity": "1", "Amount": "280" }], "Steel": [{ "Price": "18", "Quantity": "1", "Amount": "18" }], "0": "[object Object]", "1": "[object Object]" },
    result = Object.keys(allProductSpecification).reduce((r,k) => {
      if(allProductSpecification[k] !== '[object Object]')
        r[k] = allProductSpecification[k];
      return r;
    },{});
    
console.log(result);

＆＃13;

Answer 2

如果你有一个JSON字符串（不是你发布的javascript对象文字的例子）。然后你可以使用JSON.parse

的自定义复活

const json = `{
            "Vinyl_Backlite": [{
              "Price": "280",
              "Quantity": "1",
              "Amount": "280"
            }],
            "Steel": [{
              "Price": "18",
              "Quantity": "1",
              "Amount": "18"
            }],
            "0": "[object Object]",
            "1": "[object Object]"
          }`;
          
const obj = JSON.parse(json, (key, value) => (value === {}.toString() ? undefined : value))

console.log(obj)

如何根据不基于键

2 个答案: