Question

我有一个名为ShoppingList的类，我有一个购物清单列表。每个购物清单总会有3件事：第一件是水果，第二件是饮料，第三件是物品。

shopping_lists = [['apple', 'wine', 'napkins'], 
                ['Avocado', 'soda', 'apron'], ['cherry', 'orange juice', 'knife']]

然后我创建了一个名为list_of_shopping_lists的新列表，它将使用上面的shopping_lists信息接收类ShoppingList的数组。

list_of_shopping_lists = []
for my_list in shopping_lists:
    list_of_shopping_lists.append(shop_list.ShoppingList(
                                   my_list[0],my_list[1],my_list[2])

如何在不通过列表[0]，列表[1]，列表[2]的情况下更好地创建此代码？

我的类ShoppingList如下：

class ShoppingList():
    """This Class provides a way to store shopping lists."""

    # Creating constructor
    def __init__(self, fruit, drink, obj):
        self._fruit = fruit
        self._drink = drink
        self._object = obj

Answer 1

就这样做 -

list_of_shopping_lists = []
for shoping_list in shopping_lists:
    list_of_shopping_lists.append(shop_list.ShoppingList(*shoping_list))

Answer 2

使用 Python 的参数解压缩：

shopping_lists = [['apple', 'wine', 'napkins'],
                  ['Avocado', 'soda', 'apron'], 
                  ['cherry', 'orange juice', 'knife']]

class ShoppingList():
    """This Class provides a way to store shopping lists."""

    # Creating constructor
    def __init__(self, fruit, drink, obj):
        self._fruit = fruit
        self._drink = drink
        self._object = obj


list_of_shopping_lists = [ShoppingList(*sh_list) for sh_list in shopping_lists]
print(list_of_shopping_lists)

示例输出：

[<__main__.ShoppingList object at 0x000000000420FF60>, <__main__.ShoppingList object at 0x0000000004F74E48>, <__main__.ShoppingList object at 0x0000000004F556D8>]

此外，避免使用list或object命名变量/属性以防止与Python的保留名称冲突

https://docs.python.org/3.4/tutorial/controlflow.html#arbitrary-argument-lists

传递带有单词的列表以在python

2 个答案: