我想通过单个标签导航来控制两个不同的标签内容。
在Bootstra 3中,我有一个逗号分隔数据目标的解决方案(如本例中所示:https://stackoverflow.com/a/19719859/1788961)。
但是在Bootsrap 4中,这种方式不再适用于标签。
折叠组件可以使用多个目标,但我无法将其用于标签:https://getbootstrap.com/docs/4.0/components/collapse/#multiple-targets
还有其他办法吗?
这是我的代码:
<div class="B">
<div class="container">
<div class="tab-content" id="ueberTabA">
<div class="tab-pane fade" id="panel_a_first" role="tabpanel" aria-labelledby="first-tab">
A First
</div>
<div class="tab-pane fade show active" id="panel_a_second" role="tabpanel" aria-labelledby="second-tab">
A Second
</div>
<div class="tab-pane fade" id="panel_a_third" role="tabpanel" aria-labelledby="third-tab">
A Third
</div>
</div>
</div>
</div>
<div class="container">
<ul class="nav nav-tabs" id="ueberTab" role="tablist">
<li class="nav-item"><a class="nav-link" id="first-tab" data-target="#panel_b_first, #panel_a_first" data-toggle="tab" href="#first" role="tab" aria-controls="first" aria-selected="false">first</a></li>
<li class="nav-item"><a class="nav-link active" id="second-tab" data-target="#panel_b_second, #panel_a_second" data-toggle="tab" href="#second" role="tab" aria-controls="second" aria-selected="true">second</a></li>
<li class="nav-item"><a class="nav-link" id="third-tab" data-target="#panel_b_thrid, #panel_a_third" data-toggle="tab" href="#third" role="tab" aria-controls="third" aria-selected="false">Unser third</a></li>
</ul>
<div class="tab-content" id="ueberTabB">
<div class="tab-pane fade" id="panel_b_first" role="tabpanel" aria-labelledby="first-tab">
B First
</div>
<div class="tab-pane fade show active" id="panel_b_second" role="tabpanel" aria-labelledby="second-tab">
B Second
</div>
<div class="tab-pane fade" id="panel_b_thrid" role="tabpanel" aria-labelledby="third-tab">
B Third
</div>
</div>
</div>
答案 0 :(得分:1)
这在Bootstrap 4.0.0中是不可能的。这是一个悬而未决的问题,也是Bootstrap 4.1可能的“想法”。
答案 1 :(得分:1)
我实际上已经找到一种使这项工作有效的方法。这不是最漂亮的解决方案,但确实可以胜任。
这是您需要做的:
$(document).on('click', '#ueberTab a', function(e) {
otherTabs = $(this).attr('data-secondary').split(',');
for(i= 0; i<otherTabs.length;i++) {
nav = $('<ul class="nav d-none" id="tmpNav"></ul>');
nav.append('<li class="nav-item"><a href="#" data-toggle="tab" data-target="' + otherTabs[i] + '">nav</a></li>"');
nav.find('a').tab('show');
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="B">
<div class="container">
<div class="tab-content" id="ueberTabA">
<div class="tab-pane fade" id="panel_a_first" role="tabpanel" aria-labelledby="first-tab">
A First
</div>
<div class="tab-pane fade show active" id="panel_a_second" role="tabpanel" aria-labelledby="second-tab">
A Second
</div>
<div class="tab-pane fade" id="panel_a_third" role="tabpanel" aria-labelledby="third-tab">
A Third
</div>
</div>
</div>
</div>
<div class="container">
<ul class="nav nav-tabs" id="ueberTab" role="tablist">
<li class="nav-item"><a class="nav-link" id="first-tab" data-target="#panel_b_first" data-secondary="#panel_a_first" data-toggle="tab" href="#first" role="tab" aria-controls="first" aria-selected="false">first</a></li>
<li class="nav-item"><a class="nav-link active" id="second-tab" data-target="#panel_b_second" data-secondary="#panel_a_second" data-toggle="tab" href="#second" role="tab" aria-controls="second" aria-selected="true">second</a></li>
<li class="nav-item"><a class="nav-link" id="third-tab" data-target="#panel_b_thrid" data-secondary="#panel_a_third" data-toggle="tab" href="#third" role="tab" aria-controls="third" aria-selected="false">Unser third</a></li>
</ul>
<div class="tab-content" id="ueberTabB">
<div class="tab-pane fade" id="panel_b_first" role="tabpanel" aria-labelledby="first-tab">
B First
</div>
<div class="tab-pane fade show active" id="panel_b_second" role="tabpanel" aria-labelledby="second-tab">
B Second
</div>
<div class="tab-pane fade" id="panel_b_thrid" role="tabpanel" aria-labelledby="third-tab">
B Third
</div>
</div>
</div>