Question

如何转动结果查询？

目前看起来像这样

Hours | Volume
8     | 1000
9     | 1012 
10    | 1045
11    | 1598
12    | 1145
13    | 1147

进入这个

8   |9   |10  |11  |12  |13
1000|1012|1045|1598|1145|1147

我尝试了以下但是它不能正常工作

Select #TEMP.volume,
       pvt.volume,
          #TEMP.volume
          pvt.volume
FROM #TEMP
PIVOT (volume FOR [DialHour] IN ( "8", "9", "10", "11","12","13","14","15","16","17","18","19")) AS pvt

Answer 1

你可以在technet上找到一个明确的例子; https://technet.microsoft.com/en-us/library/ms177410(v=sql.105).aspx

您的代码应该更像下面的内容;

Select volume, [8], [9], [10], [11],[12],[13],[14],[15],[16],[17],[18],[19]
FROM 
(SELECT volume FROM #TEMP) AS SourceTable
PIVOT
(
hours 
FOR volume IN ("8", "9", "10", "11","12","13","14","15","16","17","18","19")
) AS PivotTable;

Answer 2

我在T-SQL中创建此表以进行演示。

CREATE TABLE #TEMP (HOURS INT, VOLUME INT)
INSERT INTO #TEMP VALUES
(8 ,1000),
(9 ,1012), 
(10,1045),
(11,1598),
(12,1145),
(13,1147)
;

如果您不使用T-SQL（SQL Server），则可能会遇到Pivot示例的问题。不同平台的语法不同。这是一种更标准的方法。

SELECT
 MAX(CASE WHEN HOURS = 8  THEN VOLUME END) AS [8]
,MAX(CASE WHEN HOURS = 9  THEN VOLUME END) AS [9]
,MAX(CASE WHEN HOURS = 10 THEN VOLUME END) AS [10]
,MAX(CASE WHEN HOURS = 11 THEN VOLUME END) AS [11]
,MAX(CASE WHEN HOURS = 12 THEN VOLUME END) AS [12]
,MAX(CASE WHEN HOURS = 13 THEN VOLUME END) AS [13]
FROM #TEMP
;

最好用字母字符标记整数/数字，而不是依赖于括号。这种方法适用于任何平台。

SELECT
 MAX(CASE WHEN HOURS = 8  THEN VOLUME END) AS COL_8
,MAX(CASE WHEN HOURS = 9  THEN VOLUME END) AS COL_9
,MAX(CASE WHEN HOURS = 10 THEN VOLUME END) AS COL_10
,MAX(CASE WHEN HOURS = 11 THEN VOLUME END) AS COL_11
,MAX(CASE WHEN HOURS = 12 THEN VOLUME END) AS COL_12
,MAX(CASE WHEN HOURS = 13 THEN VOLUME END) AS COL_13
FROM #TEMP
;

Answer 3

除了ID列之外，使用数据透视查询总是好的，为了简化你可以这样得到结果集

WITH cte
AS (
    SELECT *
    FROM #TEMP
    PIVOT(max(volume) FOR [DialHour] IN (
                "8"
                ,"9"
                ,"10"
                ,"11"
                ,"12"
                ,"13"
                ,"14"
                ,"15"
                ,"16"
                ,"17"
                ,"18"
                ,"19"
                )) AS pvt
    )
SELECT 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19...
FROM cte

Answer 4

这假设您正在使用 SQL Server ，那么使用动态 PIVOT 方法总是更好

declare @col nvarchar(max), @query nvarchar(max)

select @col = stuff(
                      (select ','+quotename(Hours) from #tm for xml path('')),
                       1,1, '')

set @query =   N'select * from
                (
                  select * from #tm
                )a 
                PIVOT
                (
                  MAX(Volume) for Hours in ('+@col+')
                )pvt'

EXECUTE sp_executesql @query

结果：

8       9       10      11      12      13
1000    1012    1045    1598    1145    1147

SQL中的数据透视表（列结果为行）

4 个答案: