Question

从数据库postgressql我得到日期的某个时间日期在不同的不同形式，如“2015-11-26 09:30:10”，“2015-11-26 09：30：10.080”，“2015-11- 26 09：30：10.000“现在我想将所有格式转换为仅格式22/01/2018如何在java中进行。

    try {
        Date theDate1 = new Date("JAN 13,2014 09:15");
        SimpleDateFormat format1 = new SimpleDateFormat("dd/MM/yyyy");
        String temp = format1.format(theDate1);
        System.out.println("Hello, World! " + temp);
    } catch (Exception e {
        System.out.println(e.toString());
    }

我输出为Hello，World！13/01 / 2014但是当我尝试

时

    try {
        Date theDate1 = new Date("2017-11-27 00:00:00");
        SimpleDateFormat format1 = new SimpleDateFormat("dd/MM/yyyy");
        String temp = format1.format(theDate1);
        System.out.println("Hello, World! " + temp);
    } catch (Exception e) {
        System.out.println(e.toString());
    }

然后我得到java.lang.IllegalArgumentExceptionhow来解决这个问题

Answer 1

试试这个

    String text = "JAN 13,2014 09:15";
    String patternst = "\\d\\d\\d\\d-\\d\\d-\\d\\d*";
    Pattern pattern = Pattern.compile(patternst);
    Matcher matcher = pattern.matcher(text);
    String data = "";
    while (matcher.find()) {
        data = matcher.group(0);
    }
    try {
        int year = Integer.parseInt(data.split("-")[0]);
        int month = Integer.parseInt(data.split("-")[1]);
        int day = Integer.parseInt(data.split("-")[2]);
        Calendar cal = Calendar.getInstance();
        cal.set(Calendar.YEAR, year);
        cal.set(Calendar.MONTH, month);
        cal.set(Calendar.DAY_OF_MONTH, day);
        Date theDate1 = cal.getTime();
        SimpleDateFormat format1 = new SimpleDateFormat("dd/MM/yyyy");
        String temp = format1.format(theDate1);
        System.out.println("Hello, World! " + temp);
    } catch (Exception e) {
        Date theDate1 = new Date(text);
        SimpleDateFormat format1 = new SimpleDateFormat("dd/MM/yyyy");
        String temp = format1.format(theDate1);
        System.out.println("Hello, World! " + temp);
    }

如何使用java将多种格式的日期转换为一种格式

1 个答案: