Question

我一直试图将一个相当平坦的json重新安排到更深入的结构中，到目前为止没有任何成功。这是我的源数据：

[ { "id": "27", "time": "2017-12-21 07:24:00", "service_name": "prices", "version": "61f4u8e", "event": "Success" }, { "id": "28", "time": "2017-12-21 07:23:00", "service_name": "prices", "version": "21c2f7d", "event": "Fail" }, { "id": "29", "time": "2017-12-21 07:21:00", "service_name": "cart", "version": "9ff24c4", "event": "Success" } ]

结果应如下所示：

[ { "name": "cart", "data": [ { "date": "2017-12-21 07:21:00", "details": { "event": "Success", "version": "9ff24c4" } } ] }, { "name": "prices", "data": [ { "date": "2017-12-21 07:24:00", "details": { "event": "Success", "version": "61f4u8e" } }, { "date": "2017-12-21 07:23:00", "details": { "event": "Fail", "version": "21c2f7d" } } ] } ]

所以，基本上按service_name分组并稍微移动其他字段。

到目前为止，我已成功分组，但只有一个级别：

group_by(.service_name) | map({name: .[0].service_name, data: .}) 如果输入将始终具有上述示例中的所有字段，我该如何改变其他值？

Answer 1

jq 解决方案：

jq '[group_by(.service_name)[] 
    | .[0].service_name as $name 
    | { name: $name, 
        data: map({ date: .time, 
                    details: {event, version}}) 
      }]' jsonfile

输出：

[
  {
    "name": "cart",
    "data": [
      {
        "date": "2017-12-21 07:21:00",
        "details": {
          "event": "Success",
          "version": "9ff24c4"
        }
      }
    ]
  },
  {
    "name": "prices",
    "data": [
      {
        "date": "2017-12-21 07:24:00",
        "details": {
          "event": "Success",
          "version": "61f4u8e"
        }
      },
      {
        "date": "2017-12-21 07:23:00",
        "details": {
          "event": "Fail",
          "version": "21c2f7d"
        }
      }
    ]
  }
]

jq：如何将平面json转换为嵌套json

1 个答案: