Question

How to add a space between alphanumeric and non alphanumeric characters?

如何在同一问题中添加以下规则？

如果令牌以＆＃34;＆＃34;＆＃34;结束？（撇号，然后是这封信 s），然后将令牌分成两个令牌：前面的部分撇号和令牌＆＃34;＆＃34;＆＃34;
如果令牌以＆＃34; n＆＃t; t＆＃34;结尾？（n-撇号-t），然后将令牌分成两个令牌：＆＃34; n＆＃34;之前的部分，以及令牌＆＃34;不是＆＃34;
如果令牌以＆＃34;＆＃39; m＆＃34;结尾？（撇号-m），然后将令牌分成两个令牌：撇号前面的部分和令牌＆＃34; am＆＃34;
如果上述子规则均不适用，则按原样接受令牌。

以下是我的尝试：

def replacer(match):
    if match.group(1).endswith("'s"):
        return '{} '.format(match.group(1) + "'s")
    elif match.group(2).endswith("n't"):
        return '{} '.format(match.group(2) + "not")
    elif match.group(3).endswith("'m"):
        return '{} '.format(match.group(3) + "'m")
    else:
        return '{}'.format(match.group(4))
rx = re.compile(r'("\'s" | "n\'t" | "\'m")+$')

string = " ".join([rx.sub(replacer, word) for word in string.split()])
print(string)

Answer 1

结合其他答案：

import re

string1 = "John's boat hasn't any comfort. I'm pretty sure he'll sell it soon."
string2 = """John had a meeting with 3managers! %nervous:( t^ria7 #manager's."""

def replacer(item):
    if item.endswith("'s"):
        return (item[:-2],) + ("'s",)
    elif item.endswith("n't"):
        return (item[:-3],) + ("not",)
    elif item.endswith("'m"):
        return (item[:-2],) + ("am",)
    else:
        rx = re.compile(r'^(?P<nonword1>\W+)(?P<word1>.*)$|(?P<word2>.*)(?P<nonword2>\W+)$')
        match = rx.search(item)
        if match is None:
            return (item,)

        if match.group('nonword1') is not None:
            return ('{} '.format(match.group('nonword1')), match.group('word1'),)
        else:
            return (match.group('word2'), ' {}'.format(match.group('nonword2')),)

""" tests """
parts = [token for item in string1.split() for token in replacer(item)]
new_string = " ".join(parts)
print(new_string)

parts = [token for item in string2.split() for token in replacer(item)]
new_string = " ".join(parts)
print(new_string)

这会产生

John 's boat has not any comfort  . I am pretty sure he'll sell it soon  .
John had a meeting with 3managers  ! %  nervous:( t^ria7 #  manager's.

如何将以下规则添加到＆＃34;如何在字母数字字符和非字母数字字符之间添加空格？＆＃34;

1 个答案: