Question

这是代码行：

with open('directory/filename.txt', 'w') as output:

如何制作

filename = input("Write the output file's name :")

为上面的代码工作？

Answer 1

将带有os.path.join()的输入文件名加入目录：

import os

filename = input("Write the output file's name: ")

with open(os.path.join('directory', filename), 'w') as output:
   # work on file

Answer 2

您还可以通过直接在open（）参数

中输入文件名来创建文件对象

 file = open(input("Enter Filename: "),'w')

Answer 3

>>> with open(input('fname:\n').split('.txt')[0]+'.txt','w') as f:
...     f.write('test')
...
fname:
testy

在这种情况下，即使用户输入或未输入文件扩展名，也会添加。

Answer 4

一种非常基本的方式：

directory = "directory"
filename = input("Name of file")
with open(directory + "/" + filename, "w") as output: # You could also do f"{directory}/{filename}" or use .format
    # do_something()

但我更喜欢这样的东西：

with open(pathlib.Path(pathlib.Path(directory) / filename), "w") as output:
    # do_something()

Python3：如何使用输入中的名称保存文本文件？

4 个答案: