Question

输入整数：99
  输入double：3.77
  输入字符：z
  输入字符串：你好   99 3.77 z你好

public class BasicInput {

    public static void main(String[] args) {
        Scanner scnr = new Scanner(System.in);
        int userInt = 99;
        double userDouble = 3.77;
        char userChar='z';
        String userString="Howdy";


        System.out.println("Enter integer: ");
        userInt = scnr.nextInt();

        System.out.print("Enter double : ");
        userDouble = scnr.nextDouble();

        System.out.print("Enter Character, ");
        userChar = scnr.next().charAt(0);

        System.out.print("Enter String, ");
        userString = scnr.next();

        System.out.println(userInt+" "+userDouble+" "+userChar+" "+userString);

        System.out.println(userString+" "+userChar+" "+userDouble+" "+userInt);

        int castInt = (int) userDouble;

        System.out.println(""+userDouble+" cast to an integer is "+castInt);

        return;

    }
}

尝试解决输入整数：

线程“main”java.util.InputMismatchException中的异常 at java.util.Scanner.throwFor（Scanner.java:864）在java.util.Scanner.next（Scanner.java:1485）在java.util.Scanner.nextInt（Scanner.java:2117）在java.util.Scanner.nextInt（Scanner.java:2076）在BasicInput.main（BasicInput.java:13）

Answer 1

详细了解您收到的例外情况： https://docs.oracle.com/javase/7/docs/api/java/util/InputMismatchException.html

由扫描程序抛出，表示检索到的令牌没有匹配预期类型的模式，或者令牌不在预期类型的范围。

试图绕过错误：“main”java.util.InputMismatchException

1 个答案: