Question

我编写了一个基本脚本，通过numpy生成一个33到255之间整数的方形矩阵在python3中生成。我可以很容易地达到这一点，但问题是下一个：我尝试用方形矩阵中的ASCII符号转换这个数字。但在Internet或StackOver Flow中搜索后，我找不到解决方案。这是我的代码：

#!usr/bin/env/python3.6
# imports
import numpy as np
import random
# Generated random matrix of 25 spaces, 
# where placed ramdom number between 0 to 255,
# and store in a variable.
matrix = np.random.randint(33,255, size=(5, 5))

# This shows the matrix of integer numbers.
print(matrix) # Good!!!
# This translate  matrix of number to ASCII table symbols:
for matrix in store:
    print(chr(matrix)) # BANG! Error, my honey.

Answer 1

这个

dtype = np.uint16 if np.dtype('U1').itemsize==2 else np.uint32
matrix.astype(dtype).view('U1')
array([['Ö', '´', 'O', 'i', '\x98'],
       ['à', 'ü', 'S', 'm', 'æ'],
       ['ý', 'm', '#', 'ö', 'u'],
       ['±', 'l', '\x82', 'O', 'È'],
       ['h', '&', '\x82', 'ª', '\xad']],
      dtype='<U1')

有点作品。但是，不是100％确定它的ASCII。但它与chr：

相同

import pprint
>>> pprint.pprint([[chr(number) for number in row] for row in matrix])
[['Ö', '´', 'O', 'i', '\x98'],
 ['à', 'ü', 'S', 'm', 'æ'],
 ['ý', 'm', '#', 'ö', 'u'],
 ['±', 'l', '\x82', 'O', 'È'],
 ['h', '&', '\x82', 'ª', '\xad']]

我们正在做的是首先转换为uint16或uint32，因为U dtype似乎每个字符有2或4个字节。然后，我们将视图转换为U1，将数字重新解释为字符及其字符。

Answer 2

代码中的store是什么。修复此错误后，它可以正常工作

#!usr/bin/env/python3.6
# imports
import numpy as np
import random
# Generated random matrix of 25 spaces, 
# where placed ramdom number between 0 to 255,
# and store in a variable.
matrix = np.random.randint(33,255, size=(5, 5))

# This shows the matrix of integer numbers.
print(matrix) # Good!!!
# This translate  matrix of number to ASCII table symbols:
for col in range(5):
    for row in range(5):
        print(chr(matrix[row][col]), end=' ')
    print('\n') # Solved, my honey.

输出是 -

[[ 86 159  40 221 211]
 [166 224 213 252 160]
 [155 160 111 109 164]
 [ 98 190  34 250  40]
 [115 228  59 139 221]]

V ¦  b s 
 à   ¾ ä 
( Õ o " ; 
Ý ü m ú  
Ó   ¤ ( Ý

矩阵数转换为矩阵ASCII？

2 个答案: